Answer:
The tension in the string connecting block 50 to block 51 is 50 N.
Explanation:
Given that,
Number of block = 100
Force = 100 N
let m be the mass of each block.
We need to calculate the net force acting on the 100th block
Using second law of newton



We need to calculate the tension in the string between blocks 99 and 100
Using formula of force


We need to calculate the total number of masses attached to the string
Using formula for mass


We need to calculate the tension in the string connecting block 50 to block 51
Using formula of tension

Put the value into the formula



Hence, The tension in the string connecting block 50 to block 51 is 50 N.
0.19
Explanation:you will divide 3.5 and 18
Can be numbered in 2 different ways, one box represents one element, and organized by atomic number
The gravitational field strength is approximately equal to 10 N.
<u>Explanation:</u>
Gravitational field strength is the measure of gravitational force acting on any object placed on the surface of the planet. Generally, the mass of the object is considered as 1 kg.
So the gravitational field strength will be equal to the gravitational force acting on the object.
The formula for gravitational field strength is

Here g is the gravitational field strength, m is the mass of the object placed on the surface and F is the gravitational force acting on the object.
Since, the mass of any object placed on the surface of earth will be negligible compared to the mass of Earth, so the mass of the object is considered as 1 kg.
Then the g = F
And 
Here G is the gravitational constant, M is the mass of Earth and m is the mass of the object placed on the surface, while r is the radius of the Earth.


So, the gravitational field strength is approximately equal to 10 N.
- The wavelength of the red light in "nanometer" is 7×

- Wavelength is given as : 7×
meter
- 1 nanometer = (
meter)
- Let X= value of the wavelength in nanometer.
1 nanometer =
meter
X nanometer = 7×
meter
- <em>If we Cross multiply</em>
X nanometer = (
)
X= 7×
nanometer
Therefore, the wavelength in "nanometer" is 7×
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