Answer:
Option A is correct.
(The faster object encounters more resistance)
Explanation:
Option A is correct. (The faster object encounters more resistance)
Air resistance depends on various factors:
- Speed of the object
- Cross-sectional area of the object
- Shape of the object
Formula:
As the speed of the object increases the amount of Air resistance/drag increases on the object, as the above formula shows direct relation between Air resistance/drag and velocity i.e F ∝ v^2.
B. The electric potential at the given point from the proton is 2.7 x 10¹ volts
<h3>
Electric potential of the proton</h3>
The electric potential of the proton is calculated as follows;
V = kq/r
where;
- k is Coulomb's constant
- q is charge
- r is distance
V = (9 x 10⁹ x 1.6 x 10⁻¹⁹)/(5.3 x 10⁻¹¹)
V = 27.2 volts
V = 2.7 x 10¹ volts
Learn more about electric potential here: brainly.com/question/14306881
#SPJ1
F(friction) = u F(normal)
so, F(friction) = (.30)(60*9.81) = 177 N
F = ma
so, 177 = (60)a, a = 177/60 = 2.9m/s^2
v(final)^2 = v(initial)^2+2ax
so, 0 = 1.5^2 + 2(-2.9)x, x = 2.25/(2*-2.9) = -.38793 the negative indicates that the direction of accel is opposite of direction of speed.
-0.39 meters is the answer.
It would be B, the greater the mass, the more fast the orbiting object will move
D = (1/2) G T^2
= 4.9 x 169. =. 828.1 meters.
This is the official height of the Burj Khalifa in Dubai ... currently the tallest building in the world. So we know exactly which "high building" the question is talking about.
