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NeX [460]
3 years ago
8

How many grams are contained in a 0.183 mol sample of ammonium phosphate?

Chemistry
1 answer:
soldi70 [24.7K]3 years ago
7 0

Molar mass of ( NH₄)₃PO₄ = 14.01×3 + 1.01×12 + 30.97 + 16.00×4 = 149.12 g/mol. Mass of 0.183 mol ...

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1. Balance the equation, then answer the following based on the equation
Artemon [7]

Answer:

Q1. a) 4Al + 3O₂ ➟ 2Al₂O₃

b) 7.4 moles

c) 11.1 moles

Explanation:

To balance an equation, ensure that the total number of atoms of each element on both sides are equal.

Al + O₂ ➟ Al₂O₃

On the left side of the arrow, you would find the reactants while the product(s) is found on the left hand side.

<u>Reactants</u>

Al atoms: 1

O atoms: 2

<u>Product</u>

Al atoms: 2

O atoms: 3

After balancing,

4Al + 3O₂ ➟ 2Al₂O₃

We have 4 Al atoms and 6 O atoms on both sides.

b) The balanced equation tells us the mole ratio of Al to Al₂O₃.

Al: Al₂O₃

= 4: 2 (÷2 throughout)

= 2: 1

This means that for every 1 mole of Al₂O₃, 2 moles of Al is needed.

Since we need 3.7 moles of Al₂O₃,

number of moles of Al needed

= 2×3.7

= 7.4

c) 4Al + 3O₂ ➟ 2Al₂O₃

For every 4 moles of Al, 3 moles of O are needed.

For each mole of Al,

number of moles of O needed

= 3÷4

= 0.75

For 14.8 moles of Al,

number of moles of O required

= 0.75 ×14.8

= 11.1

4 0
3 years ago
which substance is composed of electrically neutral groups of ions that are held together by electrostatic forces?
BabaBlast [244]

Are there options ,it would help because there could be multiple?

4 0
3 years ago
The pH of an acid solution is 5.82. Calculate the Ka for the monoprotic acid. The initial acid concentration is 0.010 M.
blagie [28]

Answer:

The answer is

<h3>Ka = 2.29 \times  {10}^{ - 14} moldm^{ - 3}</h3>

Explanation:

The Ka of an acid when given the pH and concentration can be found by

<h3>pH =  -  \frac{1}{2}  log(Ka)  -  \frac{1}{2}  log(c)</h3>

where

c is the concentration of the acid

From the question

pH = 5.82

c = 0.010 M

Substitute the values into the above formula and solve for Ka

We have

<h3>5.82 =   - \frac{1}{2}  log(Ka)  -  \frac{1}{2}  log(0.010)</h3><h3 /><h3>-  \frac{1}{2}  log(Ka)  = 5.82 + 1</h3><h3 /><h3>-  \frac{1}{2}  log(Ka)  = 6.82</h3>

Multiply through by - 2

<h3>log(Ka)  =  - 13.64</h3>

Find antilog of both sides

We have the final answer as

<h3>Ka = 2.29 \times  {10}^{ - 14} moldm^{ - 3}</h3>

Hope this helps you

8 0
3 years ago
How do you know if a reaction is exothermic? Enter your answer in the space provided
monitta
Exothermic is a chemical reaction in which heat is released. Lighting a candle is an example of an exothermic because the flame is the heat being released. 
3 0
3 years ago
Calculate the percentage of water of crystallisation in MgSO⁴ 7H²O
Bas_tet [7]

Answer:

Formula of EPSOM salt = MgSO4.7H2O

molecular mass of MgSO4.7H2O = atomic mass of Mg + atomic mass of S + 4 × atomic mass of O + 7 { 2 × atomic mass of H + atomic mass of O }

= 24 + 32 + 4× 16 + 7{ 2 × 1 + 16 } g/mol

= (24 + 32 + 64+ 126 ) g/mol

= 246 g/mol

molecular mass of total water = 7 × ( 2× atomic mass of H + atomic mass of O )

= 7 × 18 = 126 g/mol

now ,

% mass of H2O in EPSOM salt = {total molar mass of H2O/molar mass of Epsom salts }× 100

= {126/246 } × 100

= 12600/246

= 51.21 %

Explanation:

i have done it hope it helps

7 0
3 years ago
Read 2 more answers
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