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3 years ago

10.0 g of calcium carbonate was heated. The mass of calcium oxide left was 5.6 g. Calculate the mass of

Chemistry

2 answers:

timama [110]3 years ago

8 0

Answer:

4.4g

Explanation:

Calculate the molar mass of CaCO3

40+12+(16×3)

40+12+48

100 g/mol

Calculate the molar mass of CO2

12+(16×2)

12+32

44g/mol

100g of CaCO3=44g of CO2

10g of CaCO3=10×44/100

g of CO2=440/100

=4.4g of CO2

Kipish [7]3 years ago

4 0

Answer:

4.4g

Explanation:

Mass of CaCO3 = 10g

Mass of CaO = 5.6g

Mass of CO2 =?

Mass of CaCO3 = Mass of CaO + Mass of CO2

Mass of CO2 = Mass of CaCO3 — Mass of CaO

Mass of CO2 = 10 — 5.6

Mass of CO2 = 4.4g

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How many grams of barium sulfate are produced if 25.34 mL of 0.113 M BaCl2 completely react given the reaction: BaCl2 (aq) + Na2

jeyben [28]

Answer: The amount of barium sulfate produced in the given reaction is 0.667 grams.

Explanation:

To calculate the number of moles from molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of barium chloride = 0.113 M

Volume of barium chloride = 25.34 mL = 0.02534 L (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$0.113mol/L=\frac{\text{Moles of barium chloride}}{0.02534L}\\\\\text{Moles of barium chloride}=0.00286mol$

For the given chemical reaction:

$BaCl_2(aq.)+Na_2SO_4(aq.)\rightarrow BaSO_4(s)+2NaCl(aq.)$

By Stoichiometry of the reaction:

1 mole of barium chloride is producing 1 mole of barium sulfate.

So, 0.00286 moles of barium chloride will produce = $\frac{1}{1}\times 0.00286mol=0.00286mol$ of barium sulfate.

Now, to calculate the mass of barium sulfate, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of barium sulfate = 233.38 g/mol

Moles of barium sulfate = 0.00286 moles

Putting values in above equation, we get:

$0.00286mol=\frac{\text{Mass of barium sulfate}}{233.38g/mol}\\\\\text{Mass of barium sulfate}=0.667g$

Hence, the amount of barium sulfate produced in the given reaction is 0.667 grams

4 0

4 years ago

What is equal to the number of particles in 24 grams of carbon-12? 2 moles 2:1 mole ratio 2:1 molar mass 1:2 molar volume

mariarad [96]

Answer:

The answer to your question is 2 moles of Carbon

Explanation:

Carbon-12 means it has a molecular mass of 12g / mol. Mol is defined as the number of grams of an atom in one mol.

To solve this problem, we use proportions

12 g of Carbon ---------------- 1 mol of Carbon

24 g of Carbon -------------- x

x = ( 24 g x 1 mol ) / 12 g

x = 24 / 12

x = 2 mol of Carbon

8 0

3 years ago

Which metals may be oxidized by H+ under standard-state conditions? Ag+(aq) + e– → Ag(s) E° = 0.80 V Cu2+(aq) + 2e– → Cu(s) E° =

Debora [2.8K]

Answer is: tin and zinc, because they standard potential as less than zero.
Tin and zinc are oxidized to tin and zinc cations (with +2 charge) and hydrogen anions are reduced to hydrogen molecules with neutral charge.
Zn → Zn²⁺ + 2e⁻; 2H⁺ + 2e⁻ → H₂.
Oxidation is increase of oxidation number and reduction is decrease of oxidation number.

8 0

3 years ago

Calculate the number of atoms of each 4(NH4)2S

vaieri [72.5K]

4- N
8- H
2-S
Or in 4 nitrogens, 8 hydrogens, and 2 silicons

3 0

3 years ago

Electron Dot Structures

sineoko [7]

Answer:

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Explanation:

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3 years ago