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3 years ago

A solution of CuSO4 is labelled 0.01 M. How much CuSO4 in grams, must be used to make 1 liter of solution?

Chemistry

1 answer:

Gala2k [10]3 years ago

6 0

answer: C) 1.6 g

explanation: Molarity is the moles of solute present per liter solution.

The given molarity of the solution is 0.01 M.

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A gas used to extinguish fires is composed of 75 % CO2 and 25 % N2. It is stored in a 5 m3 tank at 300 kPa and 25 °C. What is th

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Answer : The partial pressure of the $CO_2$ in the tank in psia is, 32.6 psia.

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As we are given 75 % $CO_2$ and 25 % $N_2$ in terms of volume.

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$\text{Moles of }CO_2=\frac{\text{Volume of }CO_2}{\text{Volume at STP}}=\frac{75}{22.4}=3.35mole$

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$\text{Mole fraction of }CO_2=\frac{\text{Moles of }CO_2}{\text{Moles of }CO_2+\text{Moles of }N_2}$

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$\text{Partial pressure of }CO_2=\text{Mole fraction of }CO_2\times \text{Total pressure of gas}$

$\text{Partial pressure of }CO_2=0.75mole\times 300Kpa=225Kpa=225Kpa\times \frac{0.145\text{ psia}}{1Kpa}=32.625\text{ psia}$

conversion used : (1 Kpa = 0.145 psia)

Therefore, the partial pressure of the $CO_2$ in the tank in psia is, 32.6 psia.

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