Answer:
in it's natural state it's an element
Answer: 3 meters
Explanation:
If you were to use a 3 line answer then it would look like this:
d = W/F
d = 3000/1000
d = 3 meters
Answer:
8.85437 m/s
Explanation:
m = Mass of sphere = 5 kg
h = Vertical height = 4 m
g = Acceleration due to gravity = 9.80 m/s²
Applying conservation of energy we get
![\dfrac{1}{2}mv^2=mgh](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7Dmv%5E2%3Dmgh)
![\\\Rightarrow v=\sqrt{2gh}](https://tex.z-dn.net/?f=%5C%5C%5CRightarrow%20v%3D%5Csqrt%7B2gh%7D)
![\\\Rightarrow v=\sqrt{2\times 9.8\times 4}](https://tex.z-dn.net/?f=%5C%5C%5CRightarrow%20v%3D%5Csqrt%7B2%5Ctimes%209.8%5Ctimes%204%7D)
![\\\Rightarrow v=8.85437\ m/s](https://tex.z-dn.net/?f=%5C%5C%5CRightarrow%20v%3D8.85437%5C%20m%2Fs)
The sphere's speed when it reaches the bottom of the ramp is 8.85437 m/s
Answer:
Minimum uncertainty in velocity of a proton,
Explanation:
It is given that,
A proton is confined to a space 1 fm wide, ![\Delta x=10^{-15}\ m](https://tex.z-dn.net/?f=%5CDelta%20x%3D10%5E%7B-15%7D%5C%20m)
We need to find the minimum uncertainty in its velocity. We know that the Heisenberg Uncertainty principle gives the uncertainty between position and the momentum such that,
![\Delta p.\Delta x\ge \dfrac{h}{4\pi}](https://tex.z-dn.net/?f=%5CDelta%20p.%5CDelta%20x%5Cge%20%5Cdfrac%7Bh%7D%7B4%5Cpi%7D)
Since, p = mv
![\Delta (mv).\Delta x\ge \dfrac{h}{4\pi}](https://tex.z-dn.net/?f=%5CDelta%20%28mv%29.%5CDelta%20x%5Cge%20%5Cdfrac%7Bh%7D%7B4%5Cpi%7D)
![m \Delta v.\Delta x\ge \dfrac{h}{4\pi}](https://tex.z-dn.net/?f=m%20%5CDelta%20v.%5CDelta%20x%5Cge%20%5Cdfrac%7Bh%7D%7B4%5Cpi%7D)
![\Delta v\ge \dfrac{h}{4\pi m\Delta x}](https://tex.z-dn.net/?f=%5CDelta%20v%5Cge%20%5Cdfrac%7Bh%7D%7B4%5Cpi%20m%5CDelta%20x%7D)
![\Delta v\ge \dfrac{6.63\times 10^{-34}}{4\pi \times 1.67\times 10^{-27}\times 10^{-15}}](https://tex.z-dn.net/?f=%5CDelta%20v%5Cge%20%5Cdfrac%7B6.63%5Ctimes%2010%5E%7B-34%7D%7D%7B4%5Cpi%20%5Ctimes%201.67%5Ctimes%2010%5E%7B-27%7D%5Ctimes%2010%5E%7B-15%7D%7D)
![\Delta v\ge 3.15\times 10^7\ m/s](https://tex.z-dn.net/?f=%5CDelta%20v%5Cge%203.15%5Ctimes%2010%5E7%5C%20m%2Fs)
So, the minimum uncertainty in its velocity is greater than
. Hence, this is the required solution.
V=0 v²=0, A=v-u/t. T=v-u/a. T= 0-9.32/-4.06 therefore time = 2.296 seconds