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Sphinxa [80]
3 years ago
15

Energy produced by nuclear fusion is ?

Physics
2 answers:
pentagon [3]3 years ago
4 0
<h3><u>Answer;</u></h3>

<em>D. Produces no wastes</em>

<h3><u>Explanation;</u></h3>
  • <em><u>Nuclear fusion are nuclear reactions in which two or more atomic nuclei fuse or join to generate different atomic nuclei together with subatomic particles, such as protons or neutrons. </u></em>
  • Additionally,<em><u> nuclear fusion reactions yields lots energy.</u></em> The energy produced is usually more than the energy consumed by the reaction.
  • <em><u>Fusion power  is a form of power generation in which energy generated using fusion reactions is used to produce heat that is used in generation of electricity.</u></em> Energy from nuclear fusion reactions is not coupled by production of wastes.
andrey2020 [161]3 years ago
4 0

Answer:

Produces no wastes

Explanation:

The reaction in which two or more than two nuclei combine to form larger nuclei along with subatomic particles is called nuclear fusion reaction. For example, when tritium and deuterium combines, then nuclear fusion occurs and hence helium forms.

Nuclear fusion process produces minimal waste or we can say that the produced waste is not so reactive. This process creates a huge amount of energy.

Hence, the correct option is (D) " Produces no wastes ".

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The vapor pressure of diethyl ether (ether) is 463.57 mm Hg at 25°C. How many grams of chlorophyll, C55H72MgN4O5, a nonvolatile,
mixer [17]

Answer:

29.4855 grams of chlorophyll

Explanation:

From Raoult's law

Mole fraction of solvent = vapor pressure of solution ÷ vapor pressure of solvent = 457.45 mmHg ÷ 463.57 mmHg = 0.987

Mass of solvent (diethyl ether) = 187.4 g

MW of diethyl ether (C2H5OC2H5) = 74 g/mol

Number of moles of solvent = mass/MW = 187.4/74 = 2.532 mol

Let the moles of solute (chlorophyll) be y

Total moles of solution = moles of solute + moles of solvent = (y + 2.532) mol

Mole fraction of solvent = moles of solvent/total moles of solution

0.987 = 2.532/(y + 2.532)

y + 2.532 = 2.532/0.987

y + 2.532 = 2.565

y = 2.565 - 2.532 = 0.033

Moles of solute (chlorophyll) = 0.033 mol

Mass of chlorophyll = moles of chlorophyll × MW = 0.033 × 893.5 = 29.4855 grams

8 0
3 years ago
Suppose someone pours 0.250 kg of 20.0ºC water (about a cup) into a 0.500-kg aluminum pan with a temperature of 150ºC. Assume th
Troyanec [42]

Answer : The temperature when the water and pan reach thermal equilibrium short time later is, 59.10^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of aluminium = 0.90J/g^oC

c_2 = specific heat of water = 4.184J/g^oC

m_1 = mass of aluminum = 0.500 kg = 500 g

m_2 = mass of water = 0.250 kg  = 250 g

T_f = final temperature of mixture = ?

T_1 = initial temperature of aluminum = 150^oC

T_2 = initial temperature of water = 20^oC

Now put all the given values in the above formula, we get:

500g\times 0.90J/g^oC\times (T_f-150)^oC=-250g\times 4.184J/g^oC\times (T_f-20)^oC

T_f=59.10^oC

Therefore, the temperature when the water and pan reach thermal equilibrium short time later is, 59.10^oC

8 0
3 years ago
A 2.50 kg ball moving at 7.50 m/s is caught by a 70.0 kg man while the man is standing on ice. What is the common velocity of th
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Answer:

V = 2.5*7.0 / ( 2.5 + 70 )

8 0
2 years ago
Which of the following is a good thermal insulator?*<br> Iron<br> Styrofoam<br> Silver<br> Graphite
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Answer: graphite

Explanation:

7 0
3 years ago
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Why is it necessary that all three thermometers were at approximately the same distance from the light bulb
iris [78.8K]
I'm assuming it was to keep the data consistent? The further you are from a heat source the less heat will get to you as the temperature tries to reach equilibrium and the waves start to spread out, so you should keep everything the same distance to get consistent results. I don't have any information so this is just my assumption
8 0
3 years ago
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