Answer:
Approximately  .
. 
Explanation:
The refractive index of the air  is approximately
 is approximately  .
.
Let  denote the refractive index of the glass block, and let
 denote the refractive index of the glass block, and let  denote the angle of refraction in the glass. Let
 denote the angle of refraction in the glass. Let  denote the angle at which the light enters the glass block from the air.
 denote the angle at which the light enters the glass block from the air.
By Snell's Law:
 .
.
Rearrange the Snell's Law equation to obtain:
 .
. 
Hence:
 .
.
In other words, the angle of refraction in the glass would be approximately  .
.
 
        
             
        
        
        
The answer to this question is:
D) Disorder
        
                    
             
        
        
        
Answer:
Initial pressure = 6 atm. Work = 0.144 J
Explanation:
You need to know the equation P1*V1=P2*V2, where P1 is the initial pressure, V1 is the initial volume, and P2 and V2 are the final pressure and volume respectively. So you can rearrange the terms and find that (1.2*0.05)/(0.01) = initial pressure = 6 atm. The work done by the system can be obtained calculating the are under the curve, so it is 0.144J
 
        
             
        
        
        
E=energy=5.09x10^5J = 509KJ 
<span>M=mass=2250g=2.25Kg </span>
<span>C=specific heat capacity of water= 4.18KJ/Kg </span>
<span>ΔT= change in temp= ? </span>
<span>E=mcΔT </span>
<span>509=(2.25)x(4.18)xΔT </span>
<span>509=9.405ΔT </span>
<span>ΔT=509/9.405=54.1degrees </span>
<span>Initial temp = 100-54 = 46 degrees </span>
<span>Hope this helps :)</span>