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Natalka [10]
3 years ago
11

In a concave mirror, if an object is located behind the center of the curvature, What is the best description of the Image forme

d?
Physics
1 answer:
kipiarov [429]3 years ago
5 0
 be either real or virtual.
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1500 kg Peugeot car is traveling at 16.67 m s ⁻¹ and accelerates to 30.56 m s ⁻¹ for 2 minutes. Calculate the impulse of the car
Elis [28]

Answer:

2084 kg*m/s

Explanation:

Impulse is change in momentum

Mathematically;

Impulse, J= F*t=mΔv   where

F= ma = 1500 * { 30.56 - 16.67}/2*60

F= 1500 *0.11575

F=  174 N

J=F*t

J= 174*120*0.1

J= 2084 kg*m/s

5 0
3 years ago
Rock X is released from rest at the top of a cliff that is on Earth. A short time later, Rock Y is released from rest from the s
MArishka [77]

Answer:

<h2>D) S increases because at all times Rock X falls with a greater speed than Rock Y</h2>

Explanation:

As we know that Stone X is dropped first and then after some time stone Y is dropped

Now we have

v_x = gt_1

similarly for Y

v_y = g(t_1 - \Delta t)

now the relative acceleration of two stones while they are in air is ZERO

also we know from above equations

v_x > v_y

so the separation between two stones will keep on increasing as the speed of X is more than the speed of Y

5 0
3 years ago
Match the element properties with their descriptions
forsale [732]

1. ability to be pounded into shapes

2. how well a substance flows

3. the mass divided by its volume

4. degree of smoothness

5. ability to dissolve in another substance

6. how shiny a material is

7. ability to be pulled into a wire

4 0
4 years ago
A child of mass m is released from rest at the top of a water slide,
Olegator [25]

Answer:

From the concept of energy conservation, Ei=Ef

Explanation:

mgh=1/2mv^2

=> v=

\sqrt{2gh}2gh

=

\sqrt{2 \times 9.8 \times 8.8}2×9.8×8.8

=

\sqrt{172.28}172.28

=13.12m/s.

5 0
3 years ago
A car traveling at a speed of 13 meters per second accelerates uniformly to a speed of 25 meters per second in 5.0 seconds.
Vlad1618 [11]
Since car is accelerating uniformly that means we it is accelerating at constant rate if you can say that way. To find its acceleration all we have to do is find difference between v1=13 m/s and v2 = 25m/s   and divide it by interval that car is taking to accelerate.

a = (v2-v1)/t = 2,4m/s^2

since car is accelerating at constat rate and truck covers same distance as car needs to accelerate from 13 to 25m that means that we can say that in that period truck travelled at cars average speed.

Vtruck = (v1 + v2)/2 = 19m/s
4 0
3 years ago
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