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Natalka [10]
3 years ago
11

In a concave mirror, if an object is located behind the center of the curvature, What is the best description of the Image forme

d?
Physics
1 answer:
kipiarov [429]3 years ago
5 0
 be either real or virtual.
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1. ¿Qué presión se ejerce sobre cada una de las cuatro patas de una mesa si su masa es de 20 kg y
mestny [16]
Tenemos.

Masa de la mesa = 20kg
Masa encima = 10kg
Masa total = 30kg
Area de cada pata = 20cm² = 20cm² * 1/10000cm² * 1m² =0,002m²

Presió(P)n que se ejerce sobre cada pata.

P =F/A
P = Masa por gravedad/A Masa = 30kg Gravedad =9,8m/s²
P =(30kg * 9,8m/s²)/0,002m²
P = 294kg * m/s²/0,002m² Pero kg *m/s² = Nw
P = 294Nw0,002m²
P = 147000 Nw/m² Pero Nw/m² = pa
p =1,47 * 10⁵ pa

Respuesta.
La presión que se ejerce sobre cada pata es de 1,47 * 10⁵pa
8 0
3 years ago
In a standard tensile test a steel rod of 22-mm diameter is subjected to a tension force of 75kN. Knowing that v = 0.30 and E =
VladimirAG [237]

Answer:

(a) Elongation of rod = 0.19732 mm

(b) Change in diameter = 0.00651 mm

Explanation:

Circular area at end of steel rod = pi * diameter^2 / 4

Area = pi * (22 * 10^-^3)/4

Area = 3.801 * 10^(-4)    meter squared

Stress = force / area

Stress = 75000 / (3.801 * 10^-4)

Stress = 197316495 Pa     OR       0.197 GPa

Modulus of elasticity = stress / strain

200 = 0.19732 / Strain

Strain = 0.0009866     (longitudinal)

(a) Strain = change in length / initial length

0.0009866 = Elongation of rod / 200

Elongation of rod = 0.19732 mm

(b) Poisson ratio = lateral strain / longitudinal strain

0.3 = lateral strain / 0.0009866

Lateral strain = 0.000296

Lateral strain = Change in diameter / original diameter

0.000296 = Change in diameter / 22

Change in diameter = 0.00651 mm

4 0
4 years ago
Read 2 more answers
What is fundamental questioning came now<br>cfy_tuhq_wjt​
Nadya [2.5K]

Answer:

juz taking points nvm no sry for u cos u too wasted point

8 0
3 years ago
Autotrophic plants do not require which of the following? solar energy carbon dioxide water oxygen NextReset
alukav5142 [94]
<span>Autotrophic plants do not require "Oxygen" as it is a waste product of the process of photosynthesis which they do.

In short, Your Final Answer would be Option D

Hope this helps!</span>
4 0
4 years ago
Why might a balloon, that is inflated almost to its capacity, pop or explode on an extremely warm day?
REY [17]
On an extremely warm day, the balloon might pop because gases expand the hotter they get, and due to its temperature it is likely to pop if it is, indeed, nearly, if not completely, filled to its capacity.  I hope this helps, have a nice day!
7 0
3 years ago
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