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joja [24]
3 years ago
13

Your friends tell you that all heavy objects sink in water. Do you agree or disagree? Explain your answer in terms of buoyant fo

rce.
Physics
2 answers:
Inessa [10]3 years ago
8 0

Answer:

Disagree

Explanation:

Concept of sink and float depends on the condition of water displaced by the objects

As we know that object will float when the weight of the object is less than the buoyancy force on it.

Also we can say that buoyancy force is the net upthrust applied by the water on the object.

This upthrust is equal to the weight of water that is displaced by the object.

So if heavy object displace more amount of water so that the weight of displaced water is more than the weight of the object then it must float on the water.

so this is not true that all heavy objects sink in water.

WITCHER [35]3 years ago
6 0
Disagree because its not about how heavy the object is and you don't know exactly how heavy, heavy is and the weight doesn't matter, its density that matters
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A wrench 0.500 m long is applied to a nut with a force of 80.0 N. Because of the cramped space, the force must be exerted upward
riadik2000 [5.3K]

Answer:

Torque, \tau=34.6\ N.m

Explanation:

It is given that,

Length of the wrench, l = 0.5 m

Force acting on the wrench, F = 80 N

The force is acting upward at an angle of 60.0° with respect to a line from the bolt through the end of the wrench. We need to find the torque is applied to the nut. We know that torque acting on an object is equal to the cross product of force and distance. It is given by :

\tau=Fr\ sin\theta

\tau=80\times 0.5\ sin(60)

\tau=34.6\ N.m

So, the torque is applied to the nut is 34.6 N.m. Hence, this is the required solution.

7 0
3 years ago
A 790kg car moving at 7 m/s takes a turn around a circle with a radius of 20 m. Determined the net force (in Newton’s) acting up
prisoha [69]

1935.5 N is the "net force" acting on a car.

<u>Explanation</u>:

Given that,  

Mass of the car is 790 kg.

Velocity of the car is 7 m/s. (v)

It turned around with 20 m. (r)  

We know that, Net force = m × a

\text { Here, acceleration of the car is radial acceleration } a_{\mathrm{rad}}=\frac{v^{2}}{r}

\mathrm{a}_{\mathrm{rad}}=\frac{7^{2}}{20}

\mathrm{a}_{\mathrm{rad}}=\frac{49}{20}

a_{\text {rad }}=2.45 \mathrm{m} / \mathrm{s}^{2}

Now, Net force = m × a

Net force = 790 × 2.45

Net force = 1935.5 N

4 0
3 years ago
A baseball with a mass of 0.80 kg is given an acceleration of 20.00 m/s. How much net force was applied to the ball
dybincka [34]

a x m = f

.80 x 20 = 16

4 0
3 years ago
Define gravitational field
MariettaO [177]
"the field of force surrounding a body of finite mass in which anotherbody would experience an attractive force that is proportional to theproduct of the masses and inversely proportional to the square of thedistance between <span>them."


</span>
4 0
3 years ago
A certain car engine delivers enough force to create 630 N⋅m of torque when the engine is operating at 3200 revolutions per minu
jekas [21]

The appropriate expression for the calculation of power by relating the angular energy in a given time.

In other words the instantaneous power of an angular accelerating body is the torque times the angular velocity

P=\tau\omega

Where

\tau = Torque

\omega =Angular speed

Our values are given by

\tau = 630Nm

\omega = 3200rev/min

The angular velocity must be transformed into radians per second then

\omega = 3200rev/min (\frac{2\pi rad}{60s})

\omega = 335.103rad/s

Replacing,

P=(630)(335.103)

P = 211.11*10^3W

P = 211.1kW

The average power delivered by the engine at this rotation rate is 211.1kW

5 0
3 years ago
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