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kari74 [83]
3 years ago
10

Complete the equation and tell which property you used (3x10)x8=_x(10x8)

Mathematics
1 answer:
Ganezh [65]3 years ago
6 0
Hi there!
I'm just gonna answer this and explain as I'm doing it.

So we have (3x10)x8= __x(10x8)
Well, first we look at what they did. They couldn't have changed the equation, but just moved things around.
Now, assuming you know your properties, I'm gonna go ahead and answer it.
(3x10)x8=3x(10x8)
^^
I used the Associative property, which basically says that when 3 or more #s are multiplied, the answer doesn't change no matter how you group the numbers. See how they just moved the numbers around, and only swapped the 3 for the 8?
 
Hope this helped!
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<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Find the two multipliers:

40% ==> 1.4

20% ==> 0.8

Multiply them:

1.4 x 0.8 = 1.12

He will make a 12% profit.

<h3><u>✽</u></h3>

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6 0
3 years ago
Eeeeeeek need help! 5/3w = -10<br><br> A. -6<br> B. -1/6<br> C. -50/3<br> D. -5/6
xenn [34]

multiply both sides by the reciprical of 5/3 so:


3/5(5/3)w=-10(3/5)

w=-30/5=  -6

5 0
3 years ago
How do I answer this??
Mandarinka [93]
We know that:
∠ABC=∠BCA=xº
∠BDC=∠BCD=xº

1) we have to find the angle ∠DBC:
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xº+xº+∠DBC=180º
2xº+∠DBC=180º
∠DBC=180º-2xº

2) we have to find the angle ∠ABD:
∠ABD=∠ABC-∠DBC
∠ABD=xº-(180º-2x)
∠ABD=xº-180º+2xº
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4 0
3 years ago
Lisa's dog has 4 squeaky toys. Two thirds of the dog's toys are squeaky toys. How many dog toys does Lisa's have in all?
viva [34]
.  Lisa's dog has 4 squeaky toys   
.  the squeaky toys are 2/3 of all the dog's toys

.  let <em>x</em> be number of all dog toys

<em>make an equation</em>
(2/3)<em>x</em> = 4   <em>← solve</em>
x=6

<em>check</em>
2/3 × 6 = 4

<u>Lisa's Dog has 6 toys in all</u>



3 0
3 years ago
Reverse the two digits of my age, divide by three, add 20, and the result is my age. How many years old am I
lapo4ka [179]

Answer:

  • 48 years old.

Step-by-step explanation:

Let the age be xy or 10x + y.

Reverse the two digits of my age, divide by three, add 20, and the result is my age, convert this to equation:

  • (10y + x)/3 + 20 = 10x + y
  • (10y + x)/3 = 10x + y - 20
  • 10y + x = 3(10x + y - 20)
  • 10y + x = 30x + 3y - 60
  • 30x - x + 3y - 10y = 60
  • 29x - 7y = 60

We should consider both x and y are between 1 and 9 since both the age and its reverse are 2-digit numbers.

Possible options for x are:

  • 29x ≥ 7*1 + 60 = 67 ⇒ x > 2, at minimum value of y,

and

  • 29x ≤ 7*9 + 60 = 123 ⇒ x < 5, at maximum value of y.

So x can be 3 or 4.

<h3>If x = 3</h3>

  • 29*3 - 7y = 60
  • 87 - 7y = 60
  • 7y = 27
  • y = 27/7, discarded as fraction.

<h3>If x = 4</h3>

  • 29*4 - 7y = 60
  • 116 - 7y = 60
  • 7y = 56
  • y = 8

So the age is 48.

6 0
2 years ago
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