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Anestetic [448]
3 years ago
5

What is the molality of a solution containing 5.0 moles of solute in 3.2 kg of solvent? Round to the nearest tenth. Don't forget

the unit.
Chemistry
1 answer:
Alisiya [41]3 years ago
4 0
The molality of the solution is a measure of its concentration that can be calculated by dividing the amount of substance in moles by the amount of the solvent in kilograms. Mathematically, this can be expressed as that of the equation below.
                              molality = amount of solute (mole) / amount of solvent (kg)
                              molality = 5 moles / 3.2 kg
                              molality = 1.5625 m
Rounding off the answer to the nearest tenths, will give the final answer of <em>1.6 m</em>. 
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<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H^o

The equation used to calculate enthalpy change is of a reaction is:

\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)]

For the given chemical reaction:

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The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(1\times \Delta H^o_f_{(Fe(s))})+(3\times \Delta H^o_f_{(CO_2(g))})]-[(3\times \Delta H^o_f_{(CO(g))})+(2\times \Delta H^o_f_{(Fe_2O_3(s))})]

The enthalpy of formation for the substances present in their elemental state is taken as 0.

Here, iron is present in its elemental state which is solid.

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