Complete question:
Coal gasification consists of the chemical transformation of solid coal into gas. The heating values of coal differ, but the higher the heating value, the higher the value of the gas produced (which is essentially methane, carbon monoxide, hydrogen, etc.). The following coal has a reported heating value of 29,770 KJ/Kg as received. Assuming that this is the gross heating value, calculate the net heating value.. Component__________Percent C___________________71
H2__________________5.6
N2__________________1.6
S____________________2.7
Ash__________________6.1
O2___________________13
Answer:
LHV = 28478.8 KJ/kg
Explanation:
The gross heating value is also the higher heating value (HHV), while the net heating value is the lower heating value (LHV).
This involves the conversion from higher heating value (HHV) to lower heating value(LHV).
Let's use the formula:
LHV = HHV - 0.212H - 0.0245M - 0.008A
We are given
HHV = 29,770 KJ/kg = 29.770MJ/kg
H = hydrogen% =5.6%
A = oxygen% = 13%
M = 0
Substituting the figures in the formula, we have:
LHV = 29.770 - 0.212*5.6 - 0.0245*0 - 0.008*13
= 29.770 - 1.1872 - 0 - 0.104
= 28.4788 MJ/kg
= 28478.8 KJ/kg
LHV = 28478.8 KJ/kg
The net heating value, LHV = 28478.8 KJ/kg
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Answer:
The given compound cannot be cocaine.
Explanation:
The chemist can comment on the nature of compound being cocaine or not from the depression in freezing point.
Depression in freezing point of is related to molality as:
Depression in freezing point = Kf X molality
Where
Kf = cryoscopic constant = 4.90°C/m
depression in freezing point = normal freezing point - freezing point of solution
depression in freezing point = 5.5-3.9 = 1.6°C
1.6°C = 4.90 X molality
we know that:
therefore
moles = 0.327X0.008 = 0.00261 mol
The molar mass of cocaine is 303.353
So the given compound cannot be cocaine.
Answer:
The activation energy
Explanation:
The activation energy is the energy hump that lies between reactants and products. It is the energy barrier that reactants must cross before they are converted into products.
Based on the collision theory, only particles that possess the activation energy are able to collide in such a way that leads to reaction.
Collision of particles having an energy content less than the activation energy of the reaction merely leads to elastic collision between such particles.
Answer is: -963,8 kJ.
Q₁ = m(Fe) · C · ΔT₁.
C - specific heat capacity of liquid iron, C(Fe) = 0,82 J/g°<span>C.
</span>m(Fe) = 575 g.
ΔT₁ = 1181 - 1825 = -644°C.
Q₁ = -859306,5 J = -859,3 kJ.
Q₂ = m(Fe) · C · ΔT₂.
ΔT₂ = 293 - 1181 = -888°C.
C - specific heat capacity, C(Fe) = 0,44 J/g°C.
Q₂ = -224664 J = -224,66 kJ.
Q₃ =- heat of fusion, ΔH = 209 J/g.
Q₃ = 120175 J = 120,17 kJ.
Q = Q₁ + Q₂ + Q₃ = -963,8 kJ.
