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ololo11 [35]
3 years ago
6

An object (even if it is not living) will resist a change in its state, either resting or in motion, this is called ____________

.
force

mass

inertia
Physics
2 answers:
Fantom [35]3 years ago
8 0

Answer:

An object (even if it is not living) will resist a change in its state, either resting or in motion, this is called <u><em>inertia</em></u>.

Explanation:

Newton's First Law states that "Every body perseveres in its state of rest or uniform rectilinear motion unless it is forced to change its state by forces printed on it." This means that for a body to leave its state of rest or uniform rectilinear motion, it is necessary for a force to act on it. For this reason Newton's First Law is known as the Law of Inertia. Inertia is the resistance that an object has to a change in its state of motion.

In other words, inertia is the ability of matter to maintain its state of rest or uniform rectilinear motion as long as there is no force acting on it. The inertia can be separated into several groups or types of inertia.  For example:

  • The inertia related to bodies in a state of rest is called static inertia.
  • The inertia related to the bodies that are in this state of motion is called dynamic inertia.

Finally, <u><em>an object (even if it is not living) will resist a change in its state, either resting or in motion, this is called inertia.</em></u>

Oksi-84 [34.3K]3 years ago
6 0

Answer:

Inertia

Explanation:

Newton’s 1st law of motion

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Answer:

86.53 m/s

Explanation:

Given:

Mass of clay (m) = 14.0 g = 0.014 kg

Mass of block (M) = 110 g = 0.110 kg

Initial speed of block (U) = 0 m/s

Sliding distance (d) = 7.50 m

Coefficient of friction between block and surface (μ) = 0.650

Let the initial speed of clay be 'u' and speed of clay and block just after collision be 'v'.

Now, momentum is conserved just before and just after collision.

Momentum just before collision = mu + 0 = mu

Momentum just after collision = (m + M)v

Therefore, mu=(M+m)v --------- (1)

Now, using newton's second law and we find the acceleration of the system.

The frictional force is given as:

f=\mu mg=-ma\\\\a=-\mu g

Now, using equation of motion, we can find the velocity just after collision.

0^2=v^2+2ad\\\\v=\sqrt{-2ad}\\\\v=\sqrt{-2\times (-\mu g)\times d}\\\\v=\sqrt{2\mu gd}

Plug in the given values and find 'v'. This gives,

v=\sqrt{2\times 0.650\times 9.8\times 7.50}\\\\v=\sqrt{95.55}=9.77\ m/s

Now, using equation (1) and substituting the given values, we get:

0.014u=(0.014+0.110)\times 9.77\\\\u=\frac{0.124\times 9.77}{0.014}\\\\u=86.53\ m/s

Therefore, the speed of the clay immediately before impact is 86.53 m/s.

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Answer:

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So we have;

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Answer:

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