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2 years ago

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A child is twirling a 0.0113-kg ball on a string in a horizontal circle whose radius is 0.147 m. The ball travels once around th

e circle in 0.388 s. (a) Determine the centripetal force acting on the ball. (b) If the speed is doubled, by what factor does the centripetal force increase

1 answer:

antiseptic1488 [7]2 years ago

8 0

Answer:

0.435 N

The centripetal force increases by a factor of 4

Explanation:

Let the centripetal force be F

F =mv^2/r

m= mass of the object

v = linear velocity of the object

r = radius of the circular path

but v = 2πr/T = 2 * 3.142 * 0.147 / 0.388

v = 2.38 m/s

F = 0.0113 * (2.38)^2/0.147

F= 0.435 N

if v= 2v

Then;

F = m(2v)^2/r

F = m4v^2/r

F= 4mv^2/r

The centripetal force increases by a factor of 4

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