A car traveling at 26 m/s starts to decelerate steadily. It comes to a complete stop in 6 seconds. What is its acceleration?
1 answer:
Alright let's start this off with our basic equation!
Accerlation (a) = ?
Initial velocity (V1)= 26 m/s
Final velocity (V2) = 0 ft/s because the car comes to a complete stop!
Time (t) = 6 seconds
The equation for acceleration is below!
a =
So now, just plug in the values!
a =
a =
a = -4.33 m/s²
Therefore, your acceleration is -4.33 m/s²!! Hope this helped and was one of the branliest answers :')
Accerlation (a) = ?
Initial velocity (V1)= 26 m/s
Final velocity (V2) = 0 ft/s because the car comes to a complete stop!
Time (t) = 6 seconds
The equation for acceleration is below!
a =
So now, just plug in the values!
a =
a =
a = -4.33 m/s²
Therefore, your acceleration is -4.33 m/s²!! Hope this helped and was one of the branliest answers :')
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Complete question:
A 200 g load attached to a horizontal spring moves in simple harmonic motion with a period of 0.410 s. The total mechanical energy of the spring–load system is 2.00 J. Find
(a) the force constant of the spring and (b) the amplitude of the motion.
Answer:
(a) the force constant of the spring = 47 N/m
(b) the amplitude of the motion = 0.292 m
Explanation:
Given;
mass of the spring, m = 200g = 0.2 kg
period of oscillation, T = 0.410 s
total mechanical energy of the spring, E = 2 J
The angular speed is calculated as follows;
(a) the force constant of the spring
(b) the amplitude of the motion
E = ¹/₂kA²
2E = kA²
A² = 2E/k