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igomit [66]
3 years ago
12

A car traveling at 26 m/s starts to decelerate steadily. It comes to a complete stop in 6 seconds. What is its acceleration?

Physics
1 answer:
saul85 [17]3 years ago
5 0
Alright let's start this off with our basic equation!

Accerlation (a) = ?

Initial velocity (V1)= 26 m/s
Final velocity (V2) = 0 ft/s because the car comes to a complete stop!

Time (t) = 6 seconds

The equation for acceleration is below!
a = \frac{Final velocity - Initial Velocity}{time}

So now, just plug in the values! 
a = \frac{0 - 26}{6}
a = \frac{-26}{6}
a = -4.33 m/s²

Therefore, your acceleration is -4.33 m/s²!! Hope this helped and was one of the branliest answers :') 

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Evaporation only occurs at the surface of a liquid
Veseljchak [2.6K]

yes

evaporation starts on the surface

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3 years ago
One runner in a relay race has a 1.50 s lead and is running at a constant speed of 3.25 m/s. The runner has 30.0 m to run before
yarga [219]
The second runner must run 3.3m/s. If the leading runner is 1.5 seconds ahead and there are 30m left, the second runner would need to run slightly faster than the lead in order to finish at the same time. To calculate this I did 30/1.5 which gave me 0.05. I added this onto the speed of the lead runner to get 3.3m/s :)
6 0
3 years ago
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A potter's wheel has the shape of a solid uniform disk of mass 13.0 kg and radius 1.25 m. It spins about an axis perpendicular t
Fittoniya [83]

Answer:10.82 kg-m^2

Explanation:

Given

Mass of solid uniform disk M=13 kg

radius of disk r=1.25 m

mass of lump m=1.7 kg

distance of lump from axis r_0=0.63

Moment of inertia is the distribution of mass from the axis of rotation

Initial moment of inertia of disk I_1=\frac{Mr^2}{2}

I_1=\frac{13\times 1.25^2}{2}=10.15 kg-m^2

Final moment of inertia I_f=Moment of inertia of disk+moment of inertia of lump about axis

I_f=\frac{Mr^2}{2}+mr_0^2

I_f=10.15+1.7\times 0.63^2

I_f=10.15+0.674

I_f=10.82 kg-m^2

3 0
3 years ago
An inclined plane makes an angle of 30.0º with the horizontal. 
Wittaler [7]

The force required to push the box upward is 145.3N and the force to pus the box downward is -109.3N

Data given;

  • mass = 15kg
  • angle = 30 degree
  • acceleration = 1.2 m/s^2
  • acceleration due to gravity = 9.8 m/s^2

<h3>Force against gravity</h3>

To move the plane upward, the box will move against gravity.

F = F - mgcos X\\&#10;ma = F - mg cosX

Let's solve for F

ma = F - mgcosX\\&#10;15*1.2 = F - 15*9.8 * cos 30\\&#10;18 = F - 127.30\\&#10;F = 18 + 127.30\\&#10;F = 145.3N

<h3>Force towards gravity</h3>

When the force pushes the box down the inclined plane, it moves towards gravity.

F = F + mgcosX\\&#10;ma = F + mgcosX\\&#10;15*1.2 = F + 15*9.8*cos30\\&#10;F = -109.3N

The force required to push the box upward is 145.3N and the force required to push the box downward is -109.3N

Learn more on force across an inclined plane here;

brainly.com/question/11888124

4 0
3 years ago
Annie has a soccer ball and a kickball. She kicks each ball with the same force. The soccer ball accelerates at 3 m/s2, and the
klasskru [66]

Answer:

a= F/m

Explanation:

Newton's Second Law of Motion : It states that that the rate of change of momentum of a body is proportional to the applied force and it takes place on the direction of the force applied.

Mathematically,

F = m ( v-u)/t

F = ma

a = F/m

The same force was applied to each of the balls yet, the acceleration of one was greater than the other. The kickball accelerated at a greater pace than the soccer ball because it has a lesser mass hence the effect or impact of the force applied will be greatly felt by the kickball.

7 0
3 years ago
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