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Answer:
0.09 m/s to the right
Explanation:
The principle of conservation of linear momentum states that in a system of colliding objects, the total momentum before collision is equal to the total momentum after collision, provided there is no external force.
The total momentum, in this question, is the sum of the momentum of the the two marbles. We assume velocity to the right is positive while to the left is negative. Thus, total initial momentum is
After collision, the first marble goes left. Let the velocity of the other marble be v. Then we have
Equating both momenta,
Hence, the larger goes right with a velocity of 0.09 m/s (since it has a positive sign).
Answer:
The recoil velocity of the projectile is 0.0025m/s
Explanation:
Given:
Mass of the projectile =0.005kg
Mass of the launcher = 1500kg
Velocity = 750 m/s.
To Find:
The recoil velocity of the projectile = ?
Solution:
The recoil velocity is the obtained by dividing the "recoil momentum" by the "mass of the recoil body". The recoil momentum is equal to the momentum of the other body. The momentum of the other body is equal to it mass times its velocity.
Lets find the recoil momentum,
Recoil momentum = mass of the projectile X velocity
Recoil momentum =
Recoil momentum = 3.75
Now Recoil Velocity,
Recoil Velocity =
Recoil Velocity =
Recoil Velocity = 0.0025m/s
To give a solution to this exercise, it is necessary to apply Gauss's magnetic law in which he proposes the magnetic flux through closed surface is zero.
Our data given are as follows:
Inward flux = 13Wb
Outward flux = 22Wb
Since the field of the second flow is directed OUT of the curved side we need to subtract the values, therefore,
Flux = 22-13