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3 years ago

28. In the diagram above which symbol represents the light bulb ?

Physics

2 answers:

allochka39001 [22]3 years ago

4 0

Answer:

Light bulb - B

Battery - A

Explanation:

The electric circuit consists of a battery, an electric bulb, a switch etc. A battery act as a source of electric power. Its positive terminal is called cathode and its negative terminal is called as anode.

(28) In the given figure, B represents the light bulb.

(29) In the given figure, A represents the battery. There are some rechargeable batteries like lithium batteries, Nickel cadmium etc.

Tanzania [10]3 years ago

3 0

28. It's B
29. It's A

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Answer:

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Explanation:

a problem solving method that involves trying all possible solutions until one works is using trail and error.

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3 years ago

Read 2 more answers

A 4.00 kg block is pushed along the ceiling with a constant applied force of 85.0 N that acts at an angle of 55.0 degrees with t

steposvetlana [31]

Answer:

0.35

Explanation:

According to Newton's second law;

\sum Fx = ma

Fm - Ff =ma

Fm is the moving force = Wsin theta

Fm = 4(9.8)sin55

Fm = 32.1N

Ff is the frictional force = nmgcos theta

Ff = n(4)(9.8)cos55

Ff = 22.48n

Acceleration a = 6.0m/s²

Substitute the given values into the formula and get the coefficient of friction

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32.11-24= 23.48n

8.11 = 23.48

n = 8.11/23.48

n = 0.35

Hence the coefficient of friction is 0.35

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2 years ago

What does the slope on a speed vs. time graph represent

steposvetlana [31]

Answer:

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2 years ago

A 14.0 m uniform ladder weighing 490 N rests against a frictionless wall. The ladder makes a 63.0°-angle with the horizontal.

crimeas [40]

Answer:

Explanation:

Given:

length of ladder $r_L = 14m$

weight of ladder $F_L = 490N$

position of firefighter $r_F = 3.8m$

weight of firefighter $F_F = 820N$

angle of ladder $\alpha = 63$

Unknown:

force of the wall on the ladder $F_W$

force of friction on base of ladder $F_R$

normal force on base of ladder $F_N$

From the free body diagram of the sketch you get 3 equations:

$F_x = ma_x = F_W - F_R = 0\\ F_y = ma_y = F_N - F_F - F_L = 0\\ \tau _P = \overrightarrow{r} \times \overrightarrow{F} = r_FF_Fcos\alpha + \frac{1}{2}r_LF_Lcos\alpha - r_LF_Wsin\alpha = 0$