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Yuki888 [10]
3 years ago
9

In order to get a tree stump out of the ground, chains are connected to two trucks. One truck pulls with a force of 600 N to the

north while another truck pulls with a force of 800 N to the west. What is the net force on the stump
Physics
1 answer:
Black_prince [1.1K]3 years ago
3 0

Answer:

The net force on the stump is 1000 N.

Explanation:

Given that,

Force 1 acting on the truck, F_1=600\ N (due north)

Force 2 acting on the truck, F_2=800\ N (due west)

We need to find the net force on the stump. We know that force is a vector quantity. The net force on the stump is given by the the resultant force. It is given by :

F=\sqrt{F_1^2+F_2^2}

F=\sqrt{600^2+800^2}

F = 1000 N

So, the net force on the stump is 1000 N. Hence, this is the required solution.

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Explain why materials such as plastic foam, feathers, and fur are poor conductors of heat.
Firlakuza [10]
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7 0
3 years ago
A 2kg bowling ball rolls at a speed of 5 m/s on a roof of the building that is 40 meters tall. What is the kinetic energy
MrRa [10]
The kinetic energy is \frac 1 2 m v^2 and the height of the building doesn't matter at all.

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8 0
2 years ago
A wire, 1.0 m long, with a mass of 90 g, is under tension. A transverse wave is propagated on the wire, for which the frequency
Mice21 [21]

Answer:

T = 712.9 N

Explanation:

First, we will find the speed of the wave:

v = fλ

where,

v = speed of the wave = ?

f = frequency = 890 Hz

λ = wavelength = 0.1 m

Therefore,

v = (890 Hz)(0.1 m)

v = 89 m/s

Now, we will find the linear mass density of the wire:

\mu = \frac{m}{L}

where,

μ = linear mass density of wie = ?

m = mass of wire = 90 g = 0.09 kg

L = length of wire = 1 m

Therefore,

\mu = \frac{0.09\ kg}{1\ m}

μ = 0.09 kg/m

Now, the tension in wire (T) will be:

T = μv² = (0.09 kg/m)(89 m/s)²

<u>T = 712.9 N</u>

7 0
2 years ago
A hammer strikes one end of a thick iron rail of length 5.60 m. A microphone located at the opposite end of the rail detects two
never [62]

Answer:

A) The wave that travels through the rail reaches the microphone first.

B) separation in time between the arrivals of the two pulses is 0.01539 seconds.

Explanation:

Detailed explanation and calculation is shown in the image below

4 0
3 years ago
An electron and a second particle both move in circles perpendicular to a uniformmagnetic field. The mass of the second particle
Katarina [22]

Answer:

The change on the second particle is 2.93\times 10^{-16}\ C.

Explanation:

The period of revolution of the particle in the magnetic field is given by the formula as follows :

T=\dfrac{2\pi m}{Bq}

It is given that the magnetic field is uniform. The mass of the second particle is the same as that of a proton but thecharge of this particle is different from that of a proton.

m_s=m_p

If both particles take the same amount of time to go once around their respective circles. So,

T_e=T_s\\\\\dfrac{2\pi m_e}{Bq_e}=\dfrac{2\pi m_s}{Bq_s}\\\\\dfrac{m_e}{q_e}=\dfrac{m_p}{q_s}\\\\q_s=\dfrac{m_pq_e}{m_e}\\\\q_s=\dfrac{1.67\times 10^{-27}\times 1.6\times 10^{-19}}{9.11\times 10^{-31}}\\\\q_s=2.93\times 10^{-16}\ C

So, the change on the second particle is 2.93\times 10^{-16}\ C.

7 0
3 years ago
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