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Inga [223]
1 year ago
8

A naoh (aq) stock solution was created by dissolving 3.88 g naoh in water to create a 100.00 ml solution. what is the concentrat

ion of this solution?
Chemistry
1 answer:
Bess [88]1 year ago
5 0

0.0381g/mL will be concentration of this solution

The ratio of a solute—a substance that dissolves—to a solvent—a substance that does not dissolve—determines the concentration of a solution in chemistry. C = m/V, where C is the concentration, m is the mass of the solute dissolved, and V is the overall volume of the solution, is the accepted formula.

How to reach the solution?

First find for the density of NaOh which is 2.13 g/cm3

3.88 ÷ 2.13 = 1.82mL

100mL + 1.82mL = 101.82mL

3.88 ÷ 101.82mL = 0.0381g/mL

More about NaOh:

The extremely adaptable chemical sodium hydroxide (NaOH), sometimes referred to as caustic soda or lye, is employed in a range of manufacturing processes. A byproduct of the manufacturing of chlorine is sodium hydroxide. Numerous items that are used on a daily basis, including paper, metal, drain and oven cleansers for industry, soap, and detergents, are made with sodium hydroxide.

Learn more about Naoh here:

brainly.com/question/3366922

#SPJ4

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The biggest known human gene, is made up of about 2.4 million bases. The Human Genome Project also gave us more detailed information about chromosomes. It turns out that chromosome 1 contains the most genes, while the Y chromosome has the fewest.

Explanation:

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Why can two igneous rocks that have the same minerals but different names?
photoshop1234 [79]
C. the rock may have diferrent textures 

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Which method preserves an image of a leaf?.
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Tree sap flows over the leaf and preserves it.

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Amber would preserve the image.

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12. A beginner's bowling ball has a mass of 4.9 kg and a volume of 5.4 liters. Will it float in water,
Greeley [361]

Taking into account the definition of density and Archimedes' principle, the beginner bowling ball will float on the water.

But first it is neccesary to know that density is a quantity referred to the amount of mass in a certain volume of a substance or a solid object.

In other words, the density is the relationship between the weight (mass) of a substance and the volume that the same substance occupies.

The expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density=\frac{mass}{volume}

In this case, a beginner's bowling ball has a mass of 4.9 kg and a volume of 5.4 liters. This is:

  • mass= 4.9 kg= 4900 g (being 1 kg= 1000 kg)
  • volume= 5.4 L= 5400 mL (being 1L=1000 mL)

Replacing in the definition of density:

density=\frac{4900 g}{5400 mL}

Solving:

<u><em>density=0.907 </em></u>\frac{g}{mL}<u><em /></u>

On the other hand, Archimedes' principle says that an object immersed in a liquid experiences an upward vertical force equal to the weight of the volume of the dislodged liquid.

The sinking or floating of an object is determined by its density with respect to that of the liquid in which it is submerged.

Considering water as the liquid where the object is submerged in this case, an object with a higher density than water will sink. In contrast, an object with a lower density than water will float.

In this case, considering that water has a density of 1 \frac{g}{mL}, the bowling ball for beginners has a lower density. This indicates that, having a lower density than water, the object will float.

In summary, the beginner bowling ball will float on the water.

Learn more about density:

  • <u>brainly.com/question/952755?referrer=searchResults </u>
  • <u>brainly.com/question/1462554?referrer=searchResults</u>

5 0
3 years ago
A 215-g sample of copper metal at some temperature is added to 26.6 g of water. The initial water temperature is 22.22 oC, and t
andrezito [222]

The initial temperature of the copper metal was 27.38 degrees.

Explanation:

Data given:

mass of the copper metal sample = 215 gram

mass of water = 26.6 grams

Initial temperature of water = 22.22 Degrees

Final temperature of water = 24.44 degrees

Specific heat capacity of water = 0.385 J/g°C

initial temperature of copper material , Ti=?

specific heat capacity of water = 4.186 joule/gram °C

from the principle of:

heat lost = heat gained

heat gained by water is given by:

q water = mcΔT

Putting the values in the equation:

qwater = 26.6 x 4.186 x (2.22)

qwater = 247.19 J

qcopper = 215 x 0.385 x (Ti-24.4)

              = 82.77Ti - 2019.71

Now heat lost by metal = heat gained by water

82.77Ti - 2019.71 = 247.19

Ti = 27.38 degrees

8 0
3 years ago
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