The answer is negative 14
Answer:
0.4 m/s2
Explanation:
mass: 25kg
net force: 10 N
acceleration: ?
net force ÷ by mass= acceleration
10 N ÷ 25 Kg = 0.4 m/s2
Answer:
the initial speed of the arrow before joining the block is 89.85 m/s
Explanation:
Given;
mass of the arrow, m₁ = 49 g = 0.049 kg
mass of block, m₂ = 1.45 kg
height reached by the arrow and the block, h = 0.44 m
The gravitational potential energy of the block and arrow system;
P.E = mgh
P.E = (1.45 + 0.049) x 9.8 x 0.44
P.E = 6.464 J
The final velocity of the system after collision is calculated as;
K.E = ¹/₂mv²
6.464 = ¹/₂(1.45 + 0.049)v²
6.464 = 0.7495v²
v² = 6.464 / 0.7495
v² = 8.6244
v = √8.6244
v = 2.937 m/s
Apply principle of conservation of linear momentum to determine the initial speed of the arrow;

Therefore, the initial speed of the arrow before joining the block is 89.85 m/s
The objects that look black are all tied for first place.
Sunlight is broken into 3 concepts visible light, ultraviolet light, and infrared radiation