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TiliK225 [7]
3 years ago
6

Please help the question is the picture below.

Physics
2 answers:
balu736 [363]3 years ago
8 0

Its 30 kg cause I got 30 kg dude.

Mariulka [41]3 years ago
8 0

i’ve done it on paper.

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A force AB of length 100m and weight 600N has its centre of gravity 4.0 m from the end, and lies on horizontal ground calculate
Stells [14]

Answer:

F = 24 N

Explanation:

In this exercise we have a bar l = 100 m with a center of gravity x = 4 m, which force is needed to lift it from the other end

Let's use the rotational equilibrium relationship, where we consider the counterclockwise rotations as positive and fix the reference system at the point closest to the center of gravity

           ∑ τ = 0

           F l -x W = 0

           F = \frac{x}{l} \  W

let's calculate

          F = \frac{4}{100}4/100 600

          F = 24 N

8 0
3 years ago
According to​ Newton's Law of​ Cooling, if a body with temperature Upper T 1 is placed in surroundings with temperature Upper T
lesantik [10]

Answer:

27.22 F.

Explanation:

T ( t ) = T₀ + ( T₁ - T₀)e^{-kt}

T ( t ) = 41 ,  T₀ = 0 , T₁ = 140 , t = 15

Put these values in the equation above

41 = ( 140 - 0 ) e^{-15k}

41/140 = e ^{-15k}

(41/140)^{1/3} = e ^{-5k}

Let after 20 minutes temperature becomes T

T = 0 + 140 e^{-k20}

T / 41 = e^{-5k }

= (41/140)^{1/3}

T = 41 X  (41/140)^{1/3}

= 27.22 F.

7 0
4 years ago
Calculate the gravitational potential energy relative to the ground when an 82 kg person climbs to the top of a 2.0 m stepladder
bezimeni [28]
Maybe 164.... not to sure though, sorry


6 0
3 years ago
Suppose a two-level system is in a bath with temperature 247 K. The energy difference between the two states is 1.1 × 10-21 J. W
Alik [6]

Answer:

The probability of higher energy state is 0.4200.

Explanation:

Given that,

Temperature = 247 K

Energy difference between two states E_{2}-E_{1}=1.1\times10^{-21}\ J

We need to calculate the probability of higher energy state

Probability of E_{1}= e^{-\beta E_{1}}

Probability of E_{2}= e^{-\beta E_{2}}

The total probability is

e^{-\beta E_{1}}+e^{-\beta E_{1}}=1

Here, E₁ = lower energy state

E₂ = higher energy state

Put the value of E₁ in to the formula

e^{-\beta(E_{2}-1.1\times10^{-21})}+e^{-\beta E_{1}}=1

e^{-\beta E_{2}}(e^{\beta 1.1\times10^{-21}}+1)=1

e^{\beta E_{2}}=\dfrac{1}{1+e^{\dfrac{1.1\times10^{-21}}{KT}}}

Here, \beta=\dfrac{1}{KT}

Put the value into the formula

e^{\beta E_{2}}=\dfrac{1}{1+e^{\dfrac{1.1\times10^{-21}}{1.380\times10^{-23}\times247}}}

e^{\beta E_{2}}=0.4200

Hence, The probability of higher energy state is 0.4200.

4 0
3 years ago
What metals does a magnetic attract
Licemer1 [7]

Answer:

Ferromagnetic metals Hope this helps :) <3

Explanation:

4 0
3 years ago
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