All categories

3 years ago

Since prehistoric times what has been the correlation between atmospheric carbon dioxide level and global temperature

Physics

1 answer:

kondaur [170]3 years ago

6 0

Answer:

The correlation based on one source of estimates of temperatures and CO2 levels (namely the Vostok data) is <em>positive</em> with an R^2 coefficient of about 0.75.

Explanation

There are only few sources of data for us to estimate this correlation over long periods of time. One of these are the "Vostok" ice core data that span some 400 thousand years of estimated temperature and CO2 levels (https://cdiac.ess-dive.lbl.gov/trends/co2/vostok.html). A paper referenced below shows the coefficient of determination of 0.75.

It should be pointed out that a correlation, and even more so causality between historical CO2 and temperatures has been subject of an ongoing scientific debate. This debate is further compounded by politically motivated factors. So it remains to be added: use care adopting conclusions of others in this active field of science, try to perform own analysis of raw/original sources yourself, whenever possible.

Reference: https://www.researchgate.net/publication/23226792_Global_warming_and_carbon_Dioxide_through_sciences

You might be interested in

A disk rotates at constant angular acceleration, from angular position θ1 = 16.0 rad to angular position θ2 = 76.0 rad in 5.30 s

Oliga [24]

Answer:

(a) the angular velocity at θ1 is 11.64 rad/s

(b) the angular acceleration is 0.12 rad/ $s^{2}$

(c) the angular position was the disk initially at rest is - 428.27 rad

Explanation:

Given information :

θ1 = 16 rad

θ2 = 76 rad

ω2 = 11 rad/s

t = 5.3 s

(a) The angular velocity at θ1

First, we use the angular motion equation for constant acceleration

Δθ = (ω1+ω2)t/2

θ2 - θ1 = (ω1+ω2)t/2

ω1 + ω2 = 2 (θ2 - θ1) / t

ω1 = (2 (θ2 - θ1) / t ) - ω2

= (2 (76-16) / 5.3) - 11

= 11.64 rad/s

(b) the angular acceleration

ω2 = ω1 + α t

α t = ω2 - ω1

α = (ω2 - ω1)/t

= (11.64 - 11) / 5.3

= 0.12 rad/ $s^{2}$

(c) the angular position was the disk initially at rest, θ0

at rest ω0 = 0

ω2^2 = ω01 t + 2 α Δθ

2 α Δθ = ω2^2

θ2 - θ0 = ω2^2 / 2 α

θ0 = θ2 - (ω2^2) / 2 α

= 76 - ( $11^{2}$ / 2 x 0.12

= 76 - 504.16

= - 428.27 rad

4 0

4 years ago

A child does 350J of work while pulling a box from the ground up to his tree house with a rope. The tree house is 5.2 m above th

Advocard [28]

I think the answer to that questions is B.

3 0

3 years ago

It’s upside down, I know.

Paladinen [302]

Where's the question?

3 0

4 years ago

If an oscillating mass has a frequency of 1.25 Hz, it makes 100 oscillations in

KatRina [158]

Answer:

Time, t = 80 seconds

Explanation:

Given that,

The frequency of the oscillating mass, f = 1.25 Hz

Number of oscillations, n = 100

We need to find the time in which it makes 100 oscillations. We know that the frequency of an object is number of oscillations per unit time. It is given by :

$f=\dfrac{n}{t}$

$t=\dfrac{n}{f}$

$t=\dfrac{100}{1.25\ Hz}$

t = 80 seconds

So, it will make 100 oscillations in 80 seconds. Hence, this is the required solution.

4 0

3 years ago

The mass of a certain neutron star is 2.5x10^30kg and the radius 7000m. what is the force of gravity on a 1kg object of the surf

Makovka662 [10]

Answer:

3.42N

Explanation:

*not too sure bc i left my physics notes at school so it might not be 100% accurate :p*

Use the equation: F = (GMm)/(r^2)

F = force of gravity

G = gravitational constant (6.7x10^-11)

M = mass1 (2.5x10^30kg)

m = mass2 (1kg)

r = radius (7000m)

Plug it in: F = ((6.7x10^-11)(2.5x10^30)(1)) / (7000^2)

F = (1.675x10^20) / (4.9x10^7)

F = 3.4183673x10^12

F = 3.42N

8 0

3 years ago