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sukhopar [10]
3 years ago
12

Anna drives north at a speed of 50 km/h for the first hour. Then, she drives north for a second hour but slows down to 30 km/h.

Compare or contrast the first hour of her trip to the second hour of her trip.
Group of answer choices

The distance is greater in the first hour because her speed is faster.

The distance is greater in the second hour because her speed is slower.

The displacement is the same for both hours because she is travelling north the entire time.

The distances are the same for both hours because she is travelling north the entire time.
Physics
2 answers:
8090 [49]3 years ago
8 0

Answer:

The correct answer is A The distance is greater in the first hour because her speed is faster.

Explanation:

During the first hour, Anna is driving at a speed of 50 km/h. During the second hour, she is only driving at a speed of 30 km/h. The faster she goes, the farther she will go.

Hope this helps,

♥<em>A.W.E.</em><u><em>S.W.A.N.</em></u>♥

kkurt [141]3 years ago
3 0

Answer:

The distance is greater in the first hour because her speed is faster.

Explanation:

As we know that the distance of an object is given as

d = speed \times time

here we know that in first hour speed is

v_1 = 50 km/h Towards North

So the distance moved by the car is

d_1 = 50 \times 1

d_1 = 50 km

Now similarly we have speed in next hour as

v_2 = 30 km/h Towards North

so distance will be

d_2 = v_2 t

d_2 = 30 \times 1

d_2 = 30 km

So correct answer will be

The distance is greater in the first hour because her speed is faster.

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