Answer:
Explanation:
From your other post, the complete question is:
"You are pulling a sled using a horizontal rèpe, as shown in the diagram. The rope pulls the sled. exerting a force of 50 N to the right. The snow exerts a friction force of 30 N on the sled to the left. The mass of the sled is 50 kg.
Find the sum of the force on the sled.
Determine the acceleration of the sled
.
If the sled has an initial velocity 2m/s to the right, how fast will it be traveling after 5 seconds?
"
Given the rope exerting a force of 50 N to the right and the snow exerts a friction force of 30 N to the left, the sum of forces
= 50 - 30
= 20N to the right
The mass of sled is 50 kg and force = mass * acceleration.
Acceleration = Force / mass
= 20 / 50 = 0.4 m/s^2 to the right
If the sled has an initial velocity 2m/s to the right, after 5 seconds it will be traveling at initial velocity + acceleration * time
= 2 + 0.4*5
= 4 m/s to the right
Answer: F = 2N
Explanation: If a current i is flowing in a wire of length L lying in a region of magnetic field B, then the magnetic force acting on the wire is given by
F = BIL
Please find the attached file for the solution
The answer is C why because I know it is
Given; Mass m = 65.0 Kg; acceleration a = 1.25 m/s²
Required: Force F = ?
Formula: F =ma
F = (65.0 Kg)(1.25 m/s²)
F = 81.25 N