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sammy [17]
2 years ago
12

Select the correct answer.

Chemistry
1 answer:
lara31 [8.8K]2 years ago
6 0

Yo sup??

number of protons=number of electrons =8

but this is the condition when the molecule is neutral

since it has a +3 charge now therefore no of electron is

=8-3

=5

The correct answer is option B

Hope this helps

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Can anyone help me please
JulijaS [17]

Matter either loses or absorbs energy when it changes from one state to another.

5 0
3 years ago
Read 2 more answers
Magnetite is a binary compound containing only iron and oxygen. the percent, by weight, of iron is 72.360%. what is the empirica
hram777 [196]
Answer is: <span>c. Fe</span>₃<span>O</span>₄<span>.
</span>ω(Fe) = 72,360%.
ω(O) = 100% - 72,36% = 27,64%.
For example, if we the mass of compound is 100 g:
m(Fe) = 72,36 g.
n(Fe) = m(Fe) ÷ M(Fe).
n(Fe) = 72,36 g ÷ 55,85 g/mol.
n(Fe) = 1,296 mol.
n(O) = 27,64 g ÷ 16 g/mol.
n(O) = 1,727 mol.
n(Fe) : n(O) = 1,296 mol : 1,727 mol.
n(Fe) : n(O) = 1 : 1,33 or 3 : 4.
7 0
3 years ago
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What quantity is the same among atoms of the same element?
Vedmedyk [2.9K]

Answer:

Neutrons or Neutral atoms

Explanation:

Neutral atoms of each element contain an equal number of protons and electrons. The number of protons determines an element's atomic number and is used to distinguish one element from another.

8 0
2 years ago
Please solve this problem using dimensional analysis. Show your
Citrus2011 [14]
<h3>Answer:</h3>

4.3 miles

<h3>Explanation:</h3>

We are given;

Distance of 22,704 feet

We are required to determine the number of miles in 22,704 feet

  • To convert one unit to another we use conversion factors
  • Therefore, we need to know the suitable conversion factor.
  • That is, 1 mile/5,280 feet
  • Thus, to determine the number of miles we multiply the number of feet with the conversion factor.

That is;

= 22,704 feet × 1 mile/5,280 feet

= 4.3 miles

Therefore, there are 4.3 miles in 22,704 feet

5 0
3 years ago
The half-life of phosphorus-32 is 14.30 days. how many milligrams of a 20.00 mg sample of phosphorus-32 will remain after 85.80
ZanzabumX [31]
The amount of sample that is left after a certain period of time, given the half-life, h, can be calculated through the equation.

             A(t) = A(o) (1/2)^(t/d)

where t is the certain period of time. Substituting the known values,

             A(t) = (20 mg)(1/2)^(85.80/14.30)

Solving,

           A(t) = 0.3125 mg

Hence, the answer is 0.3125 mg. 
7 0
3 years ago
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