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EastWind [94]
3 years ago
5

The reaction SO3 1g2 1 H2O1l2 h H2SO4 1AQ2 is the last step in the commercial production of sulfuric acid. the enthalpy change f

or this reaction is 2227 kj. in designing a sulfuric acid plant, is it necessary to provide for heating or cooling of the reaction mixture?
Chemistry
1 answer:
Phoenix [80]3 years ago
7 0

Answer:

Cooling

Explanation:

Now, what we know is that the reaction would be exothermic. This knowledge is extractable in two ways. We know quite well that heat is released to the environment or surroundings and also the value of the enthalpy is negative. Thus we conclude that the reaction is exothermic.

Now, since heat is released to the environment, there is the need for an apparatus that would cool down the increased surrounding temperature. Hence, we can conclude that what we need actually is to provide cooling for the reaction mixture

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goldenfox [79]
I believe D. because all the organisms that live in a lake can be a bunch of living things that would be considered a population and not a species. I canceled out B. from the get go because, I don’t believe non living organisms can be in a population ?

Please get back to me if I’m right or wrong :)
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2 years ago
What is wrong with the following explanation of an experiment? When it was heated, the sample of carbon decomposed.
Drupady [299]
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3 years ago
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just olya [345]

Answer:

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Explanation:

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6 0
3 years ago
Read 2 more answers
3. A student carries out the clay-catalyzed dehydration of cyclohexanol starting with 10 moles of cyclohexanol and obtains 500 m
IrinaK [193]

Answer:

49.45~%

Explanation:

In this case, we have to start with the <u>chemical reaction</u>:

C_6H_1_2O~->~C_6H_1_0~+~H_2O

So, if we start with <u>10 mol of cyclohexanol</u> (C_6H_1_2O) we will obtain 10 mol of cyclohexanol (C_6H_1_0). So, we can calculate the grams of cyclohexanol if we<u> calculate the molar mass:</u>

(6*12)+(10*1)=82~g/mol

With this value we can calculate the grams:

10~mol~C_6H_1_0\frac{82~g~C_6H_1_0}{1~mol~C_6H_1_0}=820~g~C_6H_1_0

Now, we have as a product 500 mL of C_6H_1_0. If we use the <u>density value</u> (0.811 g/mL). We can calculate the grams of product:

500~mL\frac{0.811~g}{1~mL}=405.5~g

Finally, with these values we can calculate the <u>yield</u>:

%~=~\frac{405.5}{820}x100~=~49.45%%= (405.5/820)*100 = 49.45 %

See figure 1

I hope it helps!

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3 years ago
Water (H2O) is made up of molecules with a bent structure, whereas hydrogen sulfide (H2S) is also made up of molecules with a be
jeka94
Śhüt ûp and go pay attention in your class
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