Answer:oxidation number H = +1
oxidation number O = -2
let x = oxidation number Cl
in HClO3
+1 + x -6 =0
x = +5
Explanation:
Answer:
The volume on the tank is 6, 20 L
Explanation:
We use the formula PV=nRT. We convert the units of pressure in kPa into atm and temperature in Celsius into Kelvin:
0°C=273K
101,325kPa---1 atm
275kPa --------x=(275kPax 1 atm)/101,325kPa= 2,71 atm
PV=nRT --> V=nRT/P
V= 0,750 mol x 0,082 l atm /K mol x 273 K/ 2, 71 atm= <em>6, 20 L</em>
Answer:
1.) Tin oxide + Carbon → Tin + Carbon monoxide.
2.) Lead oxide + Carbon → Lead + Carbon monoxide.
These equations show that the metals are being extracted by their oxides by heating with carbon. This is because the metals (Tin and Lead) are less reactive than carbon. Remember, extraction methods of metals are determined by their reactivity. Since the elements tin and lead are less reactive than carbon, the extraction process of heating with carbon is needed. Remember that when a metal heats with carbon, the carbon displaces the metal from the compound and removes the oxygen from the oxide. Leaving you with the metal and carbon monoxide.
Cd(NO₃)₂ - cadmium nitrate
n{Cd(NO₃)₂}=1 mol ⇒ n(N)=2*1= 2 mol
m(N)=n(N)*A(N)
m(N)=2*14.01=28.02 g
