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marysya [2.9K]
3 years ago
12

Solving Expressions Analytically 1 point Consider the following equation, which describes the speed of sound a in an ideal gas:

The Mach number M describes the ratio of a velocity v to the acoustic velocity or speed of sound a The Mach number can also be written in terms of the stagnation temperature To. 2 (To Combine these equations and solve symbolically for the temperature T in terms of all other quantities except M. Your answer should be stored in a variable T.result, which will be a list containing one or more syspy expressions. Prefer Te instead of T.e in this case Starter code (oick to view 1 ihport sympy Answer Type here to search

Engineering
1 answer:
WINSTONCH [101]3 years ago
6 0

Answer:

Check the explanation

Explanation:

From the question above the M describes the ratio of velocity v to the acoustic velocity or the speed sound a

M=  \frac{v}{a} this can be termed as equation 1

From the above equation squaring of both sides will be calculated in the attached image below

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The pressure gage on a 2.5-m^3 oxygen tank reads 500 kPa. Determine the amount of oxygen in the tank if the temperature is 28°C
s2008m [1.1K]

Answer:

19063.6051 g

Explanation:

Pressure = Atmospheric pressure + Gauge Pressure

Atmospheric pressure = 97 kPa

Gauge pressure = 500 kPa

Total pressure = 500 + 97 kPa = 597 kPa

Also, P (kPa) = 1/101.325  P(atm)

Pressure = 5.89193 atm

Volume = 2.5 m³ = 2500 L ( As m³ = 1000 L)

Temperature = 28 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (28.2 + 273.15) K = 301.15 K  

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

5.89193 atm × 2500 L = n × 0.0821 L.atm/K.mol × 301.15 K  

⇒n = 595.76 moles

Molar mass of oxygen gas = 31.9988 g/mol

Mass = Moles * Molar mass = 595.76 * 31.9988 g = 19063.6051 g

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