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Helga [31]
3 years ago
5

Hello Averyone Subs Chanel Me please "RezaDarmawangsa "Thanks !!​

Engineering
1 answer:
Yanka [14]3 years ago
4 0

Answer:

what kind of content? I need to know

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A differential amplifier is to have a voltage gain of 100. What will be the feedback resistance required if the input resistance
yuradex [85]

Answer:

required feedback resistance ( R2 ) = 100 k Ω

Explanation:

Given data :

Voltage gain = 100

input resistance ( R1 ) = 1 k ohms

calculate feedback resistance required

voltage gain of differential amplifier

\frac{Vout}{V2 - V1 }  = \frac{R2}{R1}

= Voltage gain =  R2/R1

= 100 = R2/1

hence required feedback resistance ( R2 ) = 100 k Ω

4 0
3 years ago
Hãy xác định điện áp ngõ ra Về và các dòng điện chạy
Vitek1552 [10]

Answer:

furi has a good reputation for any other business in a few hours of this period of time as per it and the company is not a good place to start and it will have a lot of experience and you have to make a good recovery and you can do something that you can get a lot to be able and you have a lot to

3 0
3 years ago
Acoke can with inner diameter(di) of 75 mm, and wall thickness (t) of 0.1 mm, has internal pressure (pi) of 150 KPa and is suffe
NemiM [27]

Answer:

All 3 principal stress

1. 56.301mpa

2. 28.07mpa

3. 0mpa

Maximum shear stress = 14.116mpa

Explanation:

di = 75 = 0.075

wall thickness = 0.1 = 0.0001

internal pressure pi = 150 kpa = 150 x 10³

torque t = 100 Nm

finding all values

∂1 = 150x10³x0.075/2x0,0001

= 0.5625 = 56.25mpa

∂2 = 150x10³x75/4x0.1

= 28.12mpa

T = 16x100/(πx75x10³)²

∂1,2 = 1/2[(56.25+28.12) ± √(56.25-28.12)² + 4(1.207)²]

= 1/2[84.37±√791.2969+5.827396]

= 1/2[84.37±28.33]

∂1 = 1/2[84.37+28.33]

= 56.301mpa

∂2 = 1/2[84.37-28.33]

= 28.07mpa

This is a 2 d diagram donut is analyzed in 2 direction.

So ∂3 = 0mpa

∂max = 56.301-28.07/2

= 14.116mpa

6 0
3 years ago
What Member function places a new node at the end of the linked list?
Nadusha1986 [10]
<h2>˜”*°•.˜”*°• Question •°*”˜.•°*”˜ </h2>

<em>What Member function places a new node at the end of the linked list? </em>

<h2>˜”*°•.˜”*°• Answer •°*”˜.•°*”˜</h2>

appendNode

<h2>˜”*°•.˜”*°• Explanation •°*”˜.•°*”˜</h2>

The appendNode() member function places a new node at the end of the linked list. The appendNode() requires an integer representing the current data of the node.

<h2>˜”*°•.˜”*°• Details •°*”˜.•°*”˜</h2>

Subject: Coding (?)

Grade: College

Keywords: Function, linked list, appendNode, integer

Hope this helped. <3

3 0
3 years ago
Technician A says that a voltage drop of 0.8 volts on the starter ground circuit is within specifications. Technician B says tha
Romashka-Z-Leto [24]

Answer:

Technician A is wrong

Technician B is right

Explanation:

voltage drop of 0.8 volts on the starter ground circuit is not within specifications. Voltage drop should be within the range of 0.2 V to 0.6 V but not more than that.

A spun bearing can seize itself around the crankshaft journal causing it not to move. As the car ignition system is turned on, the stater may draw high current in order to counter this seizure.

8 0
4 years ago
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