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zvonat [6]
3 years ago
11

Which of the following polyatomic ions will form an ionic compound with a single sodium ion? CO32− PO43− SO42− NO31−

Chemistry
1 answer:
Artist 52 [7]3 years ago
4 0

A single sodium ion will combine due to its charge on it

Na^+

The single sodium ion has total one positive charge on it. so it requires only one electron or can bond to one negative charge

in the given polyatomic anions

a) CO3^-2 : it has two negative charge. So it will react with two sodium ions

it will forms Na2CO3

b) PO4^-3 :it has three negative charge. So it will react with three sodium ions

it will forms Na3PO4

c) SO4^-2 : it has two negative charge. So it will react with two sodium ions

it will forms Na2SO4

d) NO3^-1: it has one negative charge. So it will react with one sodium ion

it will forms NaNO3

Hence the correct answer is

Nitrate ion will react with single sodium ion as

Na+   + NO3-  ---> NaNO3

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Besides being slow to reproduce, what else could make a population susceptible to being endangered?
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Read 2 more answers
A space air is at a temperature of 75 oF, and the relative humidity (RH) is 45%. Using calculations, find: (a) the partial press
earnstyle [38]

Answer:

A) Partial Pressure of dry air = 13.32 KPa

Partial Pressure of water vapour = 1.332 KPa

B) Humidity ratio; X = 0.0691

C) V_p = 0.8384 m³/Kg

Explanation:

A) We are given;

Temperature = 75°F

Relative Humidity = 45%

Now,to calculate the partial pressure, we will use the relationship;

Relative Humidity = (Partial Pressure/Vapour Pressure) × 100%

Making partial pressure the subject;

Partial Pressure = Relative Humidity × Vapour Pressure/100%

From the first table attached, at temperature of 75°F, the vapor pressure is 29.6 × 10^(-3) bar = 29.6 KPa

Thus;

Partial Pressure of dry air = (45 × 29.6)/100

Partial Pressure of dry air = 13.32 KPa

From online values, vapour pressure of water vapour at 75°F = 2.96 KPa

Thus;

Partial Pressure of water vapour = (45 × 2.96)/100 = 1.332 KPa

B) humidity ratio of moist air is given as;

X = 0.62198 pw / (pa - pw)  

where;

pw = partial pressure of the water vapor in moist air

pa = atmospheric pressure of the moist air

Thus;

X = (0.62198 × 1.332)/(13.32 - 1.332)  

X = 0.0691

C) Formula for moist air specific volume is;

V_p = (1 + (xRw/Ra) × RaT/p

Where;

V_p is specific volume

T is temperature = 75°F = 297.039 K

p is barometric pressure which in this case is standard sea level pressure = 101.325 KPa

pw is partial pressure of the water vapor in moist air = 1.332 KPa

Rw is individual gas constant for water = 0.4614 KJ/Kg.K

Ra is individual gas constant for air = 0.2869 KJ/Kg.K

V_p = (1 + (0.0691 * 0.4614/0.2869)) × 0.286.9 * 297.039/101.325

V_p = 0.8384 m³/Kg

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