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2 years ago

Which of the following polyatomic ions will form an ionic compound with a single sodium ion? CO32− PO43− SO42− NO31−

Chemistry

1 answer:

Artist 52 [7]2 years ago

4 0

A single sodium ion will combine due to its charge on it

Na^+

The single sodium ion has total one positive charge on it. so it requires only one electron or can bond to one negative charge

in the given polyatomic anions

a) CO3^-2 : it has two negative charge. So it will react with two sodium ions

it will forms Na2CO3

b) PO4^-3 :it has three negative charge. So it will react with three sodium ions

it will forms Na3PO4

c) SO4^-2 : it has two negative charge. So it will react with two sodium ions

it will forms Na2SO4

d) NO3^-1: it has one negative charge. So it will react with one sodium ion

it will forms NaNO3

Hence the correct answer is

Nitrate ion will react with single sodium ion as

Na+ + NO3- ---> NaNO3

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Answer:

Explanation:

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3 years ago

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3 years ago

4 Nitrogen monoxide reacts with oxygen like this:

olga2289 [7]

a. mol O₂=0.5

b. volume O₂ = 25 cm³

c. i. the total volume of the two reactants = 75 cm³

c. ii. the volume of nitrogen dioxide formed = 50 cm³

<h3>Further explanation</h3>

Reaction

2NO(gas) + O₂(gas) ⇒ 2NO₂ (gas)

mol NO = 1

From the equation, mol ratio NO : O₂ = 2 : 1, so mol O₂ :

$\tt \dfrac{1}{2}\times 1=0.5$

From Avogadro's hypothesis, at the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles

Because mol ratio NO : O₂ = 2 : 1, so volume O₂ :

$\tt \dfrac{1}{2}\times 50~cm^3=25~cm^3$

i. total volume of reactants : 25 cm³+ 50 cm³=75 cm³

ii. the volume of nitrogen dioxide formed :

mol ratio NO : NO₂ = 2 : 2, so volume NO₂ = volume NO = 50 cm³

6 0

2 years ago

Calculate the change in entropy when 1.00 kg of water at 100 ∘C is vaporized and converted to steam at 100 ∘C. Assume that the h

andrew11 [14]

Answer : The change in entropy is $6.05\times 10^3J/K$

Explanation :

Formula used :

$\Delta S=\frac{m\times L_v}{T}$

where,

$\Delta S$ = change in entropy = ?

m = mass of water = 1.00 kg

$L_v$ = heat of vaporization of water = $2256\times 10^3J/kg$

T = temperature = $100^oC=273+100=373K$

Now put all the given values in the above formula, we get:

$\Delta S=\frac{(1.00kg)\times (2256\times 10^3J/kg)}{373K}$

$\Delta S=6048.25J/K=6.05\times 10^3J/K$

Therefore, the change in entropy is $6.05\times 10^3J/K$

5 0

2 years ago

the amount of water on Earth is _______but the form and location of the water _______ as it moves through the hydrologic cycle

Lorico [155]

Hey there!

I can't be sure my answers are the exact words, but it should be something along the lines of...

The amount of water on Earth is constant, but the form and location of the water changes as it moves through the water cycle.

This means that Earth has always had the same amount of water within in, along with it being the same water the whole time. No new water was introduced to our planet. Some of our water is liquid, some is solid, and some is gas. Some is deep in the soil and some is high up in the atmosphere. Some is in rain and some is in snow.

I hope this helps!

6 0

2 years ago