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3 years ago

Who knows this I need it

Chemistry

1 answer:

arsen [322]3 years ago

5 0

1. In the first image, you can see two cacti and a javelina in the background.

2. In picture one, neither of the plants are being disturbed. In picture two, however, the smaller plant is indeed being disturbed by the javelina.

3. The javelina is not eating the cactus on the right because it is stronger in color (?).

4. The cactus the javelina was eating has disappeared.

5. In picture 3, the idle cactus blossomed.

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How does rock candy relate to the igneous rock formation?

sveta [45]

Answer:

The candy is heated then cooled, turning solid like a igneous rock.

Explanation:

6 0

3 years ago

DIA [1.3K]

V_1=49.8mL
T_1=18°C=291K
T_2=83°C=356K

Using Charles law

$\\ \sf\longmapsto V_1T_2=V_2T_1$

$\\ \sf\longmapsto V_2=V_1T_2\div T_1$

$\\ \sf\longmapsto V_2=\dfrac{49.8(356)}{291}$

$\\ \sf\longmapsto V_2=\dfrac{17728.8}{291}$

$\\ \sf\longmapsto V_2=60.9mL$

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3 years ago

Massive amounts of energy are contained in an atom's: Select one:

melamori03 [73]

Nucleus.
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4 years ago

The greater the [H*], the stronger the acid.<br> True<br> False

Law Incorporation [45]

Trueeeeeeeeeeeeeeeee!!!!!

4 0

3 years ago

A piston chamber filled with ideal gas is kept in a constant-temperature bath at 25.0°C. The piston expands from 25.0 mL to 75.0

larisa [96]

Answer : The work done by the system is, 2.2722 J

Explanation :

The expression used for work done in reversible isothermal expansion will be,

$w=nRT\ln (\frac{V_2}{V_1})$

where,

w = work done = ?

n = number of moles of gas = 0.00100 mole

R = gas constant = 8.314 J/mole K

T = temperature of gas = $25^oC=273+25=298K$

$V_1$ = initial volume of gas = 25 mL

$V_2$ = final volume of gas = 75 mL

Now put all the given values in the above formula, we get:

$w=0.00100mole\times 8.314J/moleK\times 298K\times \ln (\frac{75}{25})$

$w=2.722J$

Therefore, the work done by the system is, 2.2722 J

8 0

3 years ago