All categories

3 years ago

What did James Madison foresee as an important element of the political system?

Physics

2 answers:

Naddik [55]3 years ago

7 0

Answer:

Explanation:

Papessa [141]3 years ago

3 0

An important element of the political system as foreseen by James Madison is Interest groups.

Option c

<h3>Explanation:</h3>

The group of people with specific political interest is known as political interest group. Many efforts are organized to influence laws and policies of government. These political groups pass laws which benefits their own political group. This group can also be known as special interest group or advocacy groups.

The main purpose of Interest group is to influence public group. The work done by them is to educate the public and also policy makers and their issues. Many ways to fund their causes is also found. The function of interest group is to influence the policy of public in its favor.

You might be interested in

The Sun is to a planet as -

serg [7]

Answer:a

Explanation:

5 0

3 years ago

During a solar eclipse, the Moon, Earth, and Sun all lie on the same line, with the Moon between the Earth and the Sun.

lord [1]

Answer:

(a) $F_{sm} = 4.327\times 10^{20}\ N$

(b) $F_{em} = 1.983\times 10^{20}\ N$

Solution:

As per the question:

Mass of Earth, $M_{e} = 5.972\times 10^{24}\ kg$

Mass of Moon, $M_{m} = 7.34\times 10^{22}\ kg$

Mass of Sun, $M_{s} = 1.989\times 10^{30}\ kg$

Distance between the earth and the moon, $R_{em} = 3.84\times 10^{8}\ m$

Distance between the earth and the sun, $R_{es} = 1.5\times 10^{11}\ m$

Distance between the sun and the moon, $R_{sm} = 1.5\times 10^{11}\ m$

Now,

We know that the gravitational force between two bodies of mass m and m' separated by a distance 'r' is given y:

$F_{G} = \frac{Gmm'_{2}}{r^{2}}$ (1)

Now,

(a) The force exerted by the Sun on the Moon is given by eqn (1):

$F_{sm} = \frac{GM_{s}M_{m}}{R_{sm}^{2}}$

$F_{sm} = \frac{6.67\times 10^{- 11}\times 1.989\times 10^{30}\times 7.34\times 10^{22}}{(1.5\times 10^{11})^{2}}$

$F_{sm} = 4.327\times 10^{20}\ N$

(b) The force exerted by the Earth on the Moon is given by eqn (1):

$F_{em} = \frac{GM_{s}M_{m}}{R_{em}^{2}}$

$F_{em} = \frac{6.67\times 10^{- 11}\times 5.972\times 10^{24}\times 7.34\times 10^{22}}{(3.84\times 10^{8})^{2}}$

$F_{em} = 1.983\times 10^{20}\ N$

$F_{se} = \frac{GM_{s}M_{m}}{R_{es}^{2}}$

$F_{se} = \frac{6.67\times 10^{- 11}\times 1.989\times 10^{30}\times 5.972\times 10^{24}}{((1.5\times 10^{11}))^{2}}$

$F_{se} = 3.521\times 10^{20}\ N$

7 0

3 years ago

Two forces whose resultant is 100N are at right angle to eachother. if one of them makes an angle of 30° with the resultant, det

mihalych1998 [28]

Let F₁ and F₂ denote the two forces, and R the resultant force.

F₁ and F₂ point perpendicularly to one another, so their dot product is

F₁ • F₂ = 0

We're given that one of these vectors, say F₁, makes an angle with R of 30°, so that

F₁ • R = ||F₁|| ||R|| cos(30°)

But we also have

F₁ • R = F₁ • (F₁ + F₂) = (F₁ • F₁) + (F₁ • F₂) = F₁ • F₁ = ||F₁||²

So, knowing that ||R|| = 100 N, we get that

(100 N) ||F₁|| cos(30°) = ||F₁||²

(100 N) cos(30°) = ||F₁||

||F₁|| ≈ 86.6 N

(And the same would be true for F₂.)

8 0

3 years ago

Consider the following situation, in which a compass is influenced by not only the force of Earth's magnetic field, but also an

DochEvi [55]

Answer:

1) The angle of deflection will be less than 45° ( C )

2) The angle of deflection will be greater than 45° but less than 90° ( E )

Explanation:

1) Assuming that the force applied has a direction which is perpendicular to the Earth's magnetic field

∴ Fearth > Fapplied hence the angle of deflection will be < 45°

2) when the Fearth < Fapplied

the angle of deflection will be : > 45° but < 90°

6 0

3 years ago

An object with mass 'm' is moving in a circle of radius 'R' at a constant speed of 'v.' The acceleration of the object will INCR

xenn [34]

Answer:

Explanation:

The acceleration of an object is given by the formula

a = v²/r

The acceleration of the object is bound to increase, if and only if the following are changed as well.

The mass of the object is increased,

The speed of the object is increased,

The radius of the object is contrarily decreased

Taking another look at the formula, we see that if we increase the speed of the object, it increases the acceleration. And since the radius is in the denominator, it has to be reduced for the acceleration to increase

5 0

3 years ago