1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dennis_Churaev [7]
3 years ago
11

A box slides down a frictionless plane inclined at an angle θ ¸ above the horizontal. The gravitational force on the box is dire

cted
a)vertically.
b)perpendicular to the plane.
c)at an angle θ ¸ below the inclined plane.
d)parallel to the plane in the same direction as the movement of the box.
e)parallel to the plane in the opposite direction as the movement of the box.
Physics
1 answer:
anzhelika [568]3 years ago
4 0

Answer:

vertically

Explanation:

The gravitational force on any object will always be vertically. (at an angle 90-θ below the inclined plane).

<em>The force made by the inclinated plane on the box and the force made by the box on the plane will be perpendicular to the plane.</em>

<em>The force made by the inclinated plane on the box and the force made by the box on the plane will be perpendicular to the plane.The acceleration of the box will be parallel to the plane in the same direction as the movement of the box, and the fricction force will be eparallel to the plane in the opposite direction as the movement of the box.</em>

You might be interested in
Determine W (or fuel energy) required to launch a satellite of mass m at rest from a launching pad placed at the surface earth,
jeka57 [31]

Answer:

5. 9GmM/(10R)

Explanation:

m is the mass of the satellite

M is the mass of the earth

W is the energy required to launch the satellite

Energy at earth surface = Potential energy (PE) + W

W = Energy at earth surface - Potential energy (PE)

But PE = -\frac{GMm}{R}

Therefore: W = Energy at earth surface - \frac{GMm}{R}

Energy at earth surface (E) at an altitude of 5R = -\frac{GMm}{5r} +\frac{1}{2}mV^2

But V=\sqrt{\frac{GM}{5R} }

Therefore: E=-\frac{GMm}{5R}+\frac{1}{2}m(\sqrt{\frac{GM}{5R} } )^2=  -\frac{GMm}{5R}+\frac{GMm}{10R}  = -\frac{GMm}{10R}

W = E - PE

W=-\frac{GMm}{10R}-(-\frac{GMm}{R})=-\frac{GMm}{10R}+\frac{GMm}{R}=\frac{9GMm}{10R} \\W=\frac{9GMm}{10R}

7 0
3 years ago
Three point charges are arranged along the x-axis. Charge q1 = +3.00 uC is at the origin, and charge q2= -5.00 uC is at x= 0.200
artcher [175]
We have all the charges for q1, q2, and q3. 
Since k = 8.988x10^2, and N=m^2/c^2

F(1) = F (2on1) + F (3on1)

F(2on1) = k |q1 q2| / r(the distance between the two)^2
k^ | 3x10^-6 x -5 x 10^-6 |   / (.2m)^2
F(2on1) = 3.37 N

Since F1 is 7N,

F(1) = F (2on1) + F (3on1)
7N = 3.37 N + F (3on1)

Since it wil be going in the negative direction,
-7N = 3.37 N + F (3on1)
F(3on1) = -10.37N

F(3on1) = k |q1 q3| / r(the distance between the two)^2 
r^2 x F(3on1) = k |q1 q3| 
r = sqrt of k |q1 q3| / F(3on1) 
= .144 m (distance between q1 and q3)
0 - .144m 

So it's located in -.144m

Thank you for posting your question. I hope that this answer helped you. Let me know if you need more help. 
6 0
3 years ago
Read 2 more answers
The wheel of a stationary exercise bicycle at your gym makes one rotation in 0.670 s. Consider two points on this wheel: Point P
defon

Answer:

0.938 m/s.

Explanation:

Given:

ω = 1 rev in 0.67 s

In rad/s,

1 rev = 2pi rad

ω = 2pi ÷ 0.67

= 9.38 rad/s

Rp = 10 cm

= 0.1 m

V = ω × r

= 9.38 × 0.1

= 0.938 m/s.

5 0
3 years ago
Why does an energy transfer not always result in phase change?
mash [69]

Answer:

These energy exchanges are not changes in kinetic energy. They are changes in bonding energy between the molecules. "If heat is coming into a substance during a phase change, then this energy is used to break the bonds between the molecules of the substance

4 0
3 years ago
Read 2 more answers
Both high-side pressures and low-side pressures are low with the engine running and the selector set to the air-conditioning pos
elena-14-01-66 [18.8K]

Answer:

Technician A only

Explanation:

Both high-side pressures and low-side pressures are low with the engine running and the selector set to the air-conditioning position. Technician A says that the system is undercharged. Technician B says the cooling fan could be inoperative. Which technician is correct?

usually . An overcharged system will result in lower than normal low side pressures

An undercharged system will not enable  the compressor  to create pressure. As a result of the low amount of refrigerant, the cooling ability is reduced. When we say undercharged, we mean the refrigerant in the system is low, so the both the high side pressures and low side pressures will be low.

8 0
3 years ago
Other questions:
  • a 40 kilogramstudent runs up a staircase to a floor that is 5.0 meters higher than her starting point in 7.0 seconds. the studen
    10·1 answer
  • To get copper from the solid phase to the liquid phase must of the copper sample
    5·2 answers
  • Our Sun is considered a(n) _____ star.
    12·1 answer
  • A backyard swimming pool holds 165 cubic yards (yd3) of water. what is the weight of the water in pounds?
    9·1 answer
  • How many lymphatic organs are located in the abdominal cavity
    11·1 answer
  • Which law best describes this statement earth moves faster in the winter when its closest to the sun
    7·1 answer
  • Give an example of speed making a difference in the amount of kinetic energy. Tell how you know that kinetic energy amount is di
    6·2 answers
  • Find B when θ=35, E=10V, t=5, N=250, A=1.20m^2
    8·1 answer
  • HELP PLEASE!!!!
    6·1 answer
  • Emissions from alpha decay require the least amount of shielding.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!