A) Draw a pie chart that represents the two types of lung cancer. Show your working.
1 answer:
Answer:
<em>Please, check the image provided</em>
Explanation:
<u>Pie Charts</u>
They are graphic representations of quantitative results from experimental or theoretical experiences. Instead of showing a table, it's usually preferred to show a graph where the viewer can easily understand the relative relations between the parameters under study.
The chart pie is a circular shape divided into sectors whose areas are proportional to the proportions between each parameter and the total. Since the whole sector of a circle has 360°, each sector will be a proportion or ratio of that angle.
The outcome shown in the table gives us these statistics:
Small Cell Carcinoma : 15%
Non-Small Cell Carcinoma : 85%
Each category has the following angles in the chart pie
Small Cell Carcinoma : 15%*360°=54°
Non-Small Cell Carcinoma : 85%*360°=306°
The first category is shown in blue and the second in green. Please check the image below.
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Answer:
The ratio of initial to final speed of sound is given as 1.28.
Explanation:
As per the thermodynamic relation of isentropic expansion
Here
is the pressure at point 1 which is given as 2.2 MPa
is the temperature at point 1 which is given as 77 °C or 273+77=350K
is the pressure at point 1 which is given as 0.4 MPa
is the temperature at point 2 which is to be calculated
- k is the ratio of specific heats given as 1.4
Substituting values in the equation
As speed of sound c is given as
for initial to final values it is given as
As values of k and R is constant so the ratio is given as
Substituting values give
So the ratio of initial to final speed of sound is 1.28.
Answer:
5069.04 seconds
Explanation:
The parameter we are looking for is called the Orbital period of the Hubble Space Telescope.
It is given as:
where r = radius of orbit of Hubble Space Telescope
G = gravitational constant =
M = Mass of earth
We are given that:
r = radius of the earth + distance of HST from earth
r =
M =
Therefore, T will be:
The orbital period of the Hubble Space Telescope is 5069.04 seconds.