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3 years ago

How many water molecules are produced when 5.2g O2 are reacted

Chemistry

1 answer:

gtnhenbr [62]3 years ago

5 0

Answer:

Total number of water molecules produced after the reaction is 1.956×10^22 molecules of water.

Explanation:

By the reaction

H2+ 1/2 O2 → H2O

Moles of O2 = 5.2\32

⇒1 mole of O2 produce 1 mole of H2O

1 mole O2 will produce 2 mole of H2O

Therefore, 5.2\32 mole will produce ${2}\times{\frac{5.2}\times{32}}$

⇒ Molecules of H2O will be

${2}\times{\frac{5.2}{32}}$ = $\frac{x}{{6.02}\times{10^23}}$

= 1.956×10^22 moleculesof H2O.

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How did the mass change when the copper coin was made to look silver?

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We have that The the mass change when the copper coin was made to look silver is an increase in mass

Correct option C

It increased.

It is important to note that the copper coin after its cutting into shape will have a specific mass or weight and the silver coating solution will also have a net value of mass or weight

Therefore

The the mass change when the copper coin was made to look silver is an increase in mass

Correct option C

It increased.

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3 years ago

Consider the decomposition of red mercury(II) oxide under standard state conditions. )H0 T SFE ڮ( H M 0 H (a) Is the decompositi

sertanlavr [38]

The question is incomplete, complete question is :

Consider the decomposition of red mercury(II) oxide under standard state conditions.

$2HgO(s)\rightarrow 2Hg(l)+O_2(g)$

Given :

$\Delta S_{HgO}^o=70.29 J/mol K$

$\Delta S_{Hg}^o=75.9 J/mol K$

$\Delta S_{O_2}^o=205.2 J/mol K$

Enthalpy change of the reaction = ΔH = -90.83 kJ/mol

(a) Is the decomposition spontaneous under standard state conditions?

(b) Above what temperature does the reaction become spontaneous?

Answer:

a) The decomposition is spontaneous under standard state conditions.

b)The reaction will spontaneous above -419.69 Kelvins.

Explanation:

$2HgO(s)\rightarrow 2Hg(l)+O_2(g)$

Given :

$\Delta S_{HgO}^o=70.29 J/mol K$

$\Delta S_{Hg}^o=75.9 J/mol K$

$\Delta S_{O_2}^o=205.2 J/mol K$

Entropy change of the reaction ; ΔS

$\Delta S=[2\times \Delta S_{Hg}^o+1\times \Delta S_{O_2}^o]-[2\times \Delta S_{HgO}^o]$

$=[2\times 75.9 J/mol K+1\times 205.2 J/molK]-[2\times 70.29 J/molK]=216.42 J/mol K$

Enthalpy change of the reaction = ΔH = -90.83 kJ/mol = -90830 J/mol K

1 kJ = 1000 J

At standard condition the value of temperature = T = 298 K

ΔG = ΔH - TΔS

ΔG = -90830 J/mol K - 298 K × 216.42 J/mol K = -155,323.16 J/mol

ΔG < 0 ( spontaneous)

The decomposition is spontaneous under standard state conditions.

b) Above what temperature does the reaction become spontaneous

Let the ΔG = 0

Enthalpy change of the reaction = ΔH = -90.83 kJ/mol = -90830 J/mol K

ΔG = ΔH - TΔS

0 = -90830 J/mol K - T × 216.42 J/mol K

T = -419.69 K

The reaction will spontaneous above -419.69 Kelvins.

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3 years ago

A major cause of biodiversity loss and species extinction in North Caroline is due to the introduction of invasive non-native sp

aleksley [76]

Answer:

The option<u><em> D) increases reproduction of native species</em></u> is NOT an impact that an invasive non-native species has on an ecosystem.

Explanation:

Introduction of a non-native species into a stable ecosystem can be very threatful to the ecosystem. The non-native species will compete for resources with the native species of the area. As a result, there will be severe competition. The competition might lead to migration of the native species or them being endangered on the whole. Also, the introduction of a non-native species will result in the extinction of a particular prey as it will have an increase in the number of predators.

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3 years ago

Is the kool-aid man the jar or the liquid?

nataly862011 [7]

Answer:

I think both

Explanation:

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4 years ago

3 Cu + 8HNO3 g 3 Cu(NO3)2 + 2 NO + 4 H2O

Ksivusya [100]

Considering the reaction stoichiometry, the amount of moles of NO that is produced when 27 moles of HNO₃ react is 6.75 moles.

<h3 /><h3>Reaction stoichiometry</h3>

The balanced reaction is:

3 Cu + 8 HNO₃ → 3 Cu(NO₃)₂ + 2 NO + 4 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Cu: 3 moles
HNO₃: 8 moles
Cu(NO₃)₂: 3 moles
NO: 2 moles
H₂O: 4 moles

<h3>Amount of moles of NO produced</h3>

It is possible to determine the the amount of moles of NO produced by a rule of three: if by stoichiometry 8 moles of HNO₃ produce 2 moles of NO, if 27 moles of HNO₃ react how many moles of NO will be formed?

$amount of moles of NO=\frac{27 moles of HNO_{3} x 2 moles of NO}{8 moles of HNO_{3}}$

<u><em>amount of moles of NO= 6.75 moles</em></u>

In summary, the amount of moles of NO that is produced when 27 moles of HNO₃ react is 6.75 moles.

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3 years ago