Calculate the acceleration due to gravity on the moon. the moon's radius is 1.74×106m and its mass is 7.35×1022 kg.

Helga [31]

Answer:

Follows are the solution to the given question:

Explanation:

For point a:

$T= 2\pi \sqrt{\frac{m}{k}}\\\\k = \frac{4 \pi^2 m}{T^2}\\\\= \frac{4 \times (3.14)^2 \times 3}{2^2}\\\\=29.578 \ \frac{N}{m}\\\\$

For Point b:

$E=\frac{1}{2} m a^2 w^2\\\\$

$=\frac{1}{2} \times m \times a^2 \times \frac{4\pi^2}{T^2}\\\\=\frac{1}{2} \times 3 \times (0.15)^2 \times \frac{4\times 3.14^2}{2^2}\\\\=0.332 \ J$

For Point C:

$V_{max}= a w$

$= (0.15) \times \frac{2\pi}{T}\\\\= (0.15) \times \frac{2\times 3.14}{2}\\\\=0.471 \frac{m}{s}$

For point D:

$X= a \sin (wt+ \phi)\\\\0.91=0.15 \sin(\frac{2\pi}{T} \times t+\phi)\\\\0.91=0.15 \sin(\frac{2\times 3.14}{2} \times 0.5+\phi)\\\\0.60 = \sin(3.14 \times 0.5+\phi)\\\\0.60 = \sin(1.57+\phi)\\\\1.57 +\phi =\sin^{-1} 60^{\circ}\\\\1.57 +\phi = 36.86^{\circ}\\\\=35.29^{\circ}\\\\So, X=15 \sin(3.14t+35.29^{\circ}) \ cm$

5 0

3 years ago

What does density have to do with heat?

joja [24]

If you take a fluid (i.e. air or water) and heat it, the portion that is heated usually expands. The same mass takes up more volume and as a consequence the heated portion becomes less dense than the portion that is<span><span> not heated.</span> </span>

8 0

3 years ago

Read 2 more answers

What are some actions that you can take to better manage your daily spending? How does daily spending contribute to successful m

bagirrra123 [75]

To manage your money better, you can spend your money wisely. If you spend your money on smart things, your money managemnet skills will improve.

7 0

3 years ago

Read 2 more answers

A hiker walks due East for a distance of 6 km

solniwko [45]

Resultant displacement between the base camp and the cave will be 7.211 km

Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.

Her resultant displacement can be calculated using Pythagoras theorem

$H^{2} = P^{2} + B^{2}$

= $4^{2} + 6^{2}$

= 52

H = $\sqrt{52}$ = 7.211 km

Resultant displacement between the base camp and the cave will be 7.211 km

To learn more about displacement here :

brainly.com/question/13271165

#SPJ1

3 0

1 year ago

A pitcher can throw a baseball at about 90 miles/hour (about 39.6 m/s). What is the ratio of the kinetic energy to the rest ener

tester [92]

Answer:

$8.71*10^{-15}$

Explanation:

The rest energy is the energy associated with the base ball at zero velocity which is expressed as

$Rest energy=mc^{2}\\$

Note: the speed C is the speed of light which is expressed as 3*10^8

while the kinetic energy is the energy associated with the ball during its motion and is expressed as

$Kinetic energy=1/2mv^{2}$

the ratio can be expressed as

$\frac{Kinetic Energy}{Rest Energy}=\frac{\frac{1}{2}mv^{2} }{mc^{2}}\\since V=39.6m/s\\C=3*10^{8}m/s\\\frac{Kinetic Energy}{Rest Energy}=\frac{\frac{1}{2}39.6^{2} }{(3*10^8)^{2}} \\\frac{Kinetic Energy}{Rest Energy}=\frac{784.08}{9*10^{16}} \\\frac{Kinetic Energy}{Rest Energy}=8.71*10^{-15}$

5 0

4 years ago