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Umnica [9.8K]
3 years ago
8

An object is placed 250 cm in front of a concave circular mirror, and the image of the object also appears at 250 cm in front of

the mirror. What is the radius of curvature of the mirror?
500 cm
125 cm
25.0 cm
250 cm
Physics
1 answer:
Scrat [10]3 years ago
3 0

Answer:

Radius of curvature of the mirror = 250 cm

Explanation:

Given:

Object distance from mirror = 250 cm (u=-250)

Object distance appears in mirror = 250 cm (v=-250)

Find:

Radius of curvature of the mirror

Computation:

Using mirror formula

1/f = 1/v + 1/u

1/f = 1/(-250) + 1/(-250)

f = (-250/2)

f = -125 cm or 125 cm

Radius of curvature of the mirror = 2(f)

Radius of curvature of the mirror = 2(125)

Radius of curvature of the mirror = 250 cm

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G.

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Correct Answers is A.

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4 years ago
If the magnetic field is held constant at 3.0 T and the loop is pulled out of the region that contains the field in 0.2 s, what
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Answer:

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emf=|-\frac{\Delta\,\Phi}{\Delta \,t} |=|\frac{A\,B}{\Delta \,t}|=|\frac{A\,(3)}{0.2}|=15\,A

and if the area (A) is given in square meters, the emf will directly come in units of Volts.

5 0
4 years ago
An object moves in a circular path at a constant speed. What is the relationship between the directions of the object's velocity
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b

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3 0
3 years ago
Find the magnitude of u × v and the unit vector parrallel to u × v in the direction of u × v. u = 2i + 2j - k, v = -i + k
IrinaVladis [17]

Answer:

magnitude = 3

unit vector = \frac{2i}{3} - \frac{j}{3} - \frac{2k}{3}

Explanation:

Given vectors:

u = 2i + 2j - k

v = -i + k = -i + 0j + k

(a) u x v is the cross product of u and v, and is given by;

u X v = \left[\begin{array}{ccc}i&j&k\\2&2&-1\\-1&0&1\end{array}\right]

u x v = i(2+0) - j(2 - 1) + k(0 - 2)

u x v = 2i - j - 2k

Now the magnitude of u x v is calculated as follows:

| u x v | = \sqrt{2^2 + (-1)^2 + (-2)^2}

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| u x v | = \sqrt{9}

| u x v | = 3

Therefore, the magnitude of u x v is 3

(b) The unit vector û parallel to u x v in the direction of u x v is given by the ratio of u x v and the magnitude of u x v. i.e

û = \frac{u X v}{|u X v|}        

u x v = 2i - j - 2k        [<em>calculated in (a) above</em>]

|u x v| = 3                   [<em>calculated in (a) above</em>]

∴ û = \frac{2i - j - 2k}{3}

∴ û = \frac{2i}{3} - \frac{j}{3} - \frac{2k}{3}

4 0
3 years ago
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