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sleet_krkn [62]
2 years ago
12

During an isothermal process, 10 j of heat is removed from an ideal gas. What is the work done by the gas in the process?

Physics
1 answer:
Black_prince [1.1K]2 years ago
8 0

The work done in the isothermal process is 10 joule.

We need to know about the isotherm process to solve this problem. The isotherm process can be described as a process where the initial temperature system will be the same as the final temperature. Hence, the internal energy change will be zero.

ΔU = 0

Hence,

ΔU = Q - W

0 = Q - W

Q = W

It means that the heat transferred is the same as the work done.

From the question above, we know that the heat transferred is 10 joule. Thus, the work done in the isothermal process is 10 joule.

Find more on isothermal at: brainly.com/question/17097259

#SPJ4

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   x = 2,864 m ,       Ra = 32.1 m                       

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             β = 10 log Iₐ / I₀

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               Ia 4pi Ra2 = Ib 4pi Rb2

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Let us call the distance from the observer be to the haughty R = ax, so the distance from the observer A to the haughty is R = 35 ax; we substitute

             Ia (35 -x) 2 = Ib x2

we develop and solve

           35-x = Ra (Ib / Ia) x

           35 = [Ra (Ib / Ia) +1] x

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           x = 35 / 12.22

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The distance from observer A

            Ra = 35 - x

            Ra = 35 - 2,864

            Ra = 32.1 m

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