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Arte-miy333 [17]
3 years ago
5

Which type of electromagnetic waves make up the colors of a rainbow seen after a storm?

Physics
2 answers:
quester [9]3 years ago
7 0

The correct answer to the question is Visible light.

EXPLANATION:

A rainbow is visible to our naked eye. It contains all the seven constituent colors of a white light ranging from violet to red. Generally it is formed after  a storm. It is due to the fact that different colors of light has different wavelength. When the white light falls on the water particles present in the atmosphere, all the colors deviate at different angles after their refraction through water particles, and the spectrum is obtained.

The infrared wave, X- rays and ultraviolet rays are not visible to our eye.

The visible light is that electromagnetic wave which helps us to view any object. It contains the seven colors just like a rainbow i.e ranging from violet to red.

All the colors present in a rainbow corresponds to visible region of the electromagnetic spectrum .

Hence, visible light is that electromagnetic wave which makes up the colors of a rainbow seen after a storm.

Step2247 [10]3 years ago
3 0
Visible light waves are the type of electromagnetic waves that make up the colors of the rainbow, because the rainbow is visible to us.
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The aqueous humor in a person's eye is exerting a force of 0.242 N on the 1.21 cm2 area of the cornea. What pressure is this in
Virty [35]

Answer:

<h2><em>15.00124mmHg</em></h2>

Explanation:

Pressure is defined as the ratio of force applied to an object to its area.

Pressure = Force/Area

Given parameters

Force = 0.242N

Area = 1.21cm²

Required parameters

Pressure = 0.242/1.21

Pressure = 0.2N/cm²

Using the conversion to convert the pressure to mmHg

1N/cm² = 75.0062mmHg

0.2N/cm² = y

y = 0.2 * 75.0062

y = 15.00124mmHg

<em>Hence the pressure in mmHg is 15.00124mmHg</em>

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2 years ago
What were the patterns that people saw in the sky long ago?
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7 0
3 years ago
Read 2 more answers
A block of weight 1200N is on an incline plane of 30° with the horizontal, a force P is applied to the body parallel to the plan
pshichka [43]

Answer:

a)  P = 807.85 N,  b)  P = 392.15 N,  c)  P = 444.12 N

Explanation:

For this exercise, let's use Newton's second law, let's set a reference frame with the x-axis parallel to the plane and the direction rising as positive, and the y-axis perpendicular to the plane.

Let's use trigonometry to break down the weight

         sin θ = Wₓ / W

         cos θ = W_y / W

         Wₓ = W sin θ

         W_y = W cos θ

         Wₓ = 1200 sin 30 = 600 N

          W_y = 1200 cos 30 = 1039.23 N

Y axis  

      N- W_y = 0

      N = W_y = 1039.23 N

Remember that the friction force always opposes the movement

a) in this case, the system will begin to move upwards, which is why friction is static

       P -Wₓ -fr = 0

       P = Wₓ + fr

as the system is moving the friction coefficient is dynamic

      fr = μ N

      fr = 0.20 1039.23

      fr = 207.85 N

we substitute

       P = 600+ 207.85

       P = 807.85 N

b) to avoid downward movement implies that the system is stopped, therefore the friction coefficient is static

        P + fr -Wx = 0

       fr = μ N

       fr = 0.20 1039.23

        fr = 207.85 N

we substitute

        P =  Wₓ -fr

        P = 600 - 207,846

        P = 392.15 N

c) as the movement is continuous, the friction coefficient is dynamic

         P - Wₓ + fr = 0

         P = Wₓ - fr

         fr = 0.15 1039.23

         fr = 155.88 N

         P = 600 - 155.88

         P = 444.12 N

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2 years ago
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liubo4ka [24]

Answer:

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yKpoI14uk [10]
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