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omeli [17]
3 years ago
9

How do motion and Newton's laws apply to your everyday life? (all the laws)

Physics
1 answer:
Nataly [62]3 years ago
4 0

For me personally, Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air.

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Find the mass of a 52.2N bucket.​
Goshia [24]

Answer:

m = 5.22 kg

Explanation:

The force acting on the bucket is 52.2 N.

We need to find the mass of the bucket.

The force acting on the bucket is given by :

F = mg

g is acceleration due to gravity

m is mass

m=\dfrac{F}{g}\\\\m=\dfrac{52.2}{10}\\\\=5.22\ kg

So, the mass of the bucket is 5.22 kg.

3 0
3 years ago
I need help quick!! Urgent!
faltersainse [42]

C.

Explanation: Because mirrors are lighter, and they are easier than lenses to make perfectly smooth.

6 0
3 years ago
A mass weighing 24 pounds, attached to the end of a spring, stretches it 4 inches. Initially, the mass is released from rest fro
svetoff [14.1K]

Answer:

The equation of motion is x(t)=-\frac{1}{3} cos4\sqrt{6t}

Explanation:

Lets calculate

The weight attached to the spring is 24 pounds

Acceleration due to gravity is 32ft/s^2

Assume x , is spring stretched length is ,4 inches

Converting the length inches into feet x=\frac{4}{12} =\frac{1}{3}feet

The weight (W=mg) is balanced by restoring force ks at equilibrium position

mg=kx

W=kx ⇒ k=\frac{W}{x}

The spring constant , k=\frac{24}{1/3}

                            = 72

If the mass is displaced from its equilibrium position by an amount x, then the differential equation is

    m\frac{d^2x}{dt} +kx=0

    \frac{3}{4} \frac{d^2x}{dt} +72x=0

  \frac{d^2x}{dt} +96x=0

Auxiliary equation is, m^2+96=0

                                 m=\sqrt{-96}

                               =\frac{+}{} i4\sqrt{6}

Thus , the solution is x(t)=c_1cos4\sqrt{6t}+c_2sin4\sqrt{6t}

                                 x'(t)=-4\sqrt{6c_1} sin4\sqrt{6t}+c_2  4\sqrt{6} cos4\sqrt{6t}

The mass is released from the rest x'(0) = 0

                    =-4\sqrt{6c_1} sin4\sqrt{6(0)}+c_2 4\sqrt{6} cos4\sqrt{6(0)} =0

                                                    c_2 4\sqrt{6} =0

                                     c_2=0

Therefore , x(t)=c_1 cos 4\sqrt{6t}

Since , the mass is released from the rest from 4 inches

                    x(0)= -4 inches

c_1 cos 4\sqrt{6(0)} =-\frac{4}{12} feet

   c_1=-\frac{1}{3} feet

Therefore , the equation of motion is  -\frac{1}{3} cos4\sqrt{6t}

7 0
2 years ago
A body of mass 500kg moving at a speed of 10m/s reaches the speed of 50m/s in 20s.The force exerted is
Leona [35]

Answer:

answer is 1000 N

formula used-

<em><u>F= m x (v-u/t)</u></em>

<em><u>mark</u></em><em><u> </u></em><em><u>th</u></em><em><u>is</u></em><em><u> as</u></em><em><u> brainliest</u></em><em><u>!</u></em>

6 0
3 years ago
A load of 45N attached to a spring that is hanging vertically stretches the spring 0.14m. What is the spring constant?
Vesna [10]
6.3 That Would be the I answer I think but Check on Google For the formula
6 0
3 years ago
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