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Stells [14]
3 years ago
11

What would be the greatest difference in using an open ceramic coffee mug rather than an insulated mug with a lid as a calorimet

er?
1.increased evaporation of the water
2.loss of gaseous reactants
3.inability to contain liquids
4.exchange of energy with the surroundings
Chemistry
2 answers:
Ostrovityanka [42]3 years ago
8 0

HE ANSWER IS DEFINITELY D

adoni [48]3 years ago
4 0
The answer is number 4 or the exchange of energy with the surroundings. Calorimetry is a measurement of energy that is formed or absorbed in a certain process. The calorimeter is the instrument used in order to measure the energy. It is recommended that a calorimeter should be a closed system so as to measure precisely the energy and avoid or lessen the exchange of energy with the surroundings. Thus, comparing an open ceramic mug and an insulated mug with a lid, the greatest difference is the energy lost to the surroundings. 
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What may be expected when K > 1.0?
lora16 [44]

The two correct statements are:

1. The concentration of one or more of the products is small

2. The reaction will proceed to the right and favor the formation of products.

LeChatelier's Principle states that when a stress is imposed on a system at equilibrium, the equilibrium will shift to counteract the change. A reduction in the number of products cause the system to respond by making more product, which leads to K>1 and products being more favorable.

4 0
2 years ago
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(04.02 LC) Based on the cell theory, which of the following is true?
prohojiy [21]

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c

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4 0
2 years ago
A boy swings a rubber ball attached to a string over his head in a horizontal, circular path. The piece of string is 1.15 m long
gregori [183]

Answer:

v = 16.49 m/s

Explanation:

Given that,

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We need to find the tangential velocity of the ball. It can be given by

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5 0
3 years ago
Kito puts his spoon into a helping of fresh, hot, mashed potatoes as shown in the figure. Which process takes place when the two
Svet_ta [14]

Answer:

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7 0
3 years ago
Determine the pH of a 5x10^-4 M solution of Ca(OH)2
miss Akunina [59]
Ca(OH)₂ ==> Ca²⁺ + 2 OH<span>-   

Ca(OH)</span>₂ is <span>strong Bases</span><span>

</span>Therefore,  the [OH-] equals 5 x 10⁻⁴ M. For every Ca(OH)₂ you produce 2 OH⁻<span>.
</span>
pOH = - log[ OH⁻]

pOH = - log [ <span>5 x 10⁻⁴ ]

pOH = 3.30

pH + pOH = 14

pH + 3.30 = 14

pH = 14 - 3.30

pH = 10.7

hope this helps!</span>
5 0
3 years ago
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