Answer:
2.728 kg
Explanation:
The units help you keep the calculation straight.

Answer:
A. Vo = -0.606 volts
B. Vo = -0.349 volts
Explanation:
In this question, we are asked to calculate the output voltage by analyzing the conditions given and also calculate the output voltage given that one of theses conditions changed.
Please check attachment for complete solution.
Answer:
metals, composite, ceramics and polymers.
Explanation:
The four categories of engineering materials used in manufacturing are metals, composite, ceramics and polymers.
i) Metals: Metals are solids made up of atoms held by matrix of electrons. They are good conductors of heat and electricity, ductile and strong.
ii) Composite: This is a combination of two or more materials. They have high strength to weight ratio, stiff, low conductivity. E.g are wood, concrete.
iii) Ceramics: They are inorganic, non-metallic crystalline compounds with high hardness and strength as well as poor conductors of electricity and heat.
iv) Polymers: They have low weight and are poor conductors of electricity and heat
Answer:
The car has an energy of 1.017 × 10⁵ J when it moves at 97 miles per hour
Explanation:
Given the data in the question;
Initial velocity v₁ = 68 miles per hour = 30.398 meter per seconds
let mass of the car be m
kinetic energy of that car is 5 × 10⁵ J
so
E₁ =
mv²
we substitute
5 × 10⁵ =
× m × ( 30.398 )²
5 × 10⁵ =
× m × ( 30.398 )²
5 × 10⁵ = m × 462.019
m = 5 × 10⁵ / 462.019
m = 1082.2065 kg
Now, Also given that; v₂ = 97 miles per hour = 43.362 meter per seconds
E₂ =
mv₂²
we substitute
E₂ =
× 1082.2065 × ( 43.362 )²
E₂ =
× 1082.2065 × 1880.263
E₂ = 1.017 × 10⁵ J
Therefore, The car has an energy of 1.017 × 10⁵ J when it moves at 97 miles per hour
Answer:
hello the figure attached to your question is missing attached below is the missing diagram
answer :
i) 1.347 kW
ii) 1.6192 kW
Explanation:
Attached below is the detailed solution to the problem above
First step : Calculate for Enthalpy
h1 - hf = -3909.9 kJ/kg ( For saturated liquid nitrogen at 600 kPa )
h2- hg = -222.5 kJ/kg ( For saturated vapor nitrogen at 600 kPa )
second step : Calculate the rate of heat transfer in boiler
Q1-2 = m( h2 - h1 ) = 0.008( -222.5 -(-390.9) = 1.347 kW
step 3 : find the enthalpy of superheated Nitrogen at 600 Kpa and 280 K
from the super heated Nitrogen table
h3 = -20.1 kJ/kg
step 4 : calculate the rate of heat transfer in the super heater
Q2-3 = m ( h3 - h2 )
= 0.008 ( -20.1 -(-222.5 ) = 1.6192 kW