Using the count data and observational data you acquired, calculate the number of CFUs in the original sample
Answer:
I = I₀ + M(L/2)²
Explanation:
Given that the moment of inertia of a thin uniform rod of mass M and length L about an Axis perpendicular to the rod through its Centre is I₀.
The parallel axis theorem for moment of inertia states that the moment of inertia of a body about an axis passing through the centre of mass is equal to the sum of the moment of inertia of the body about an axis passing through the centre of mass and the product of mass and the square of the distance between the two axes.
The moment of inertia of the body about an axis passing through the centre of mass is given to be I₀
The distance between the two axes is L/2 (total length of the rod divided by 2
From the parallel axis theorem we have
I = I₀ + M(L/2)²
The number of kilowatts used by an individual to operate his appliances is determined as 12.1 kWh.
<h3>
Average daily power consumption</h3>
The average daily power consumption is the amount of electric energy consumed by an individual on a daily rate.
The average daily power consumption of individuals in USA is 12,100 W-hr.
<h3>Converting watts to kilowatts</h3>
E = 12,100 Whr/1000
E = 12.1 kWh
Thus, the number of kilowatts used by an individual to operate his appliances is determined as 12.1 kWh.
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The law of conservation of energy implies that energy can neither be created nor destroyed, but can be changed from one form to another.
a)You throw a stone horizontally at a speed of 5.0 m/s from the top of a cliff that is 78.4 m high.
from above statement we got
height = 78.4 m
since the ball is thrown, so its vertical velocity would be zero
u = 0
taking g = 9.8m/s^2
now, using the equation of motion
h = ut + gt^2/2
now putting all the values in it
we got ,
78.4 = 9.8 * t^2/ 2
by solving we got,
t = 4 sec
b) now, since along the horizontal , no force acting and accelaration is zero so
R = ut , R is RANGE
R = 5 * 4
range = 20 m
c) vertical components of the stone’s velocity just before it hits the ground = v sin θ =
horizontal components of the stone’s velocity just before it hits the ground = v cos θ
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