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evablogger [386]
3 years ago
6

A passenger sitting in the rear of a bus claims that he was injured when the driver slammed on the brakes,causing a suitcase to

come flying toward the passenger form the front of the bus. If you were the judge in this case, what disposition would you make
Physics
1 answer:
Natasha2012 [34]3 years ago
6 0

<span>If I will be the judge, the passenger will not be injured by suitcase came from the front of the bus because when the driver slammed the break the inertia of the force must be moving forward. It impossible for a suit case to move backwards, maybe the passenger was the one flying forward and hit something </span>

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Why were epicycles necessary in ptolemy’s model of the universe?
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epicycles were orbits within orbits used to explain discrepancies between expected and observed planetary movement, including the appearance of planets slowing down, speeding up, and moving backward.

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You are walking in Paris alongside the Eiffel Tower and suddenly a croissant falls on your head and knocks you to the ground. If
Alexxandr [17]

Answer:

7,79 seconds

Explanation:

{\displaystyle {\overline {a}}={\frac {\Delta v}{t}}}

You need to use the acceleration formula. A is acceliration, \displaystyle \Delta \mathbf {v} is change in velocity and t is time.

You  need to multiply the formula with t and divide by a and you get

a*t=\displaystyle \Delta \mathbf {v}

t= \displaystyle \Delta \mathbf {v}/a

after that you just need to insert the numbers

change in velocity is 76.4 minus 0.

acceliration is gravitational acceleration which is 9.81.

After that you get

t=76.4/9.81

t= 7,787971458 s

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5. Electromagnetic radiation travels at a speed of 3.0 x 10^8 m/s.
creativ13 [48]

Answer:

i think its b

Explanation:

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2 years ago
Bernini's sculpture apollo and daphne implies motion. what kind of motion is being depicted?
gladu [14]
Bernini's sculpture "Apollo and Daphne" implies a chase scene motion. Apollo and Daphne<span> is a life-sized Baroque marble </span>sculpture<span> by Italian artist Gian Lorenzo </span>Bernini<span>, executed between 1622 and 1625. Hope this answers the question. Have a nice day.</span>
5 0
3 years ago
Titanium metal requires a photon with a minimum energy of 6.94×10−19J to emit electrons. If titanium is irradiated with light of
butalik [34]

Answer:

a) 1.59(10)^{-19} J

b) 2.34(10)^{12} electrons

Explanation:

The photoelectric effect consists of the emission of electrons (electric current) that occurs when light falls on a metal surface under certain conditions.  

If the light is a stream of photons and each of them has energy, this energy is able to pull an electron out of the crystalline lattice of the metal and communicate, in addition, a kinetic energy.  

<u>This is what Einstein proposed: </u>

Light behaves like a stream of particles called photons with an energy  E:

E=\frac{hc}{\lambda} (1)  

So, the energy E of the incident photon must be equal to the sum of the Work function \Phi of the metal and the kinetic energy K of the photoelectron:  

E=\Phi+K (2)  

Where \Phi=6.94(10)^{-19} J is the minimum amount of energy required to induce the photoemission of electrons from the surface of Titanium metal.

Knowing this, let's begin with the answers:

<h3 /><h3>a)  Maximum possible kinetic energy of the emitted electrons (K)</h3>

From (1) we can know the energy of one photon of 233 nm light:

E=\frac{hc}{\lambda}

Where:

h=6.63(10)^{-34}J.s is the Planck constant  

\lambda=233 (10)^{-9} m is the wavelength

c=3 (10)^{8} m/s is the speed of light

E=\frac{(6.63(10)^{-34}J.s)(3 (10)^{8} m/s)}{3 (10)^{8} m/s} (3)

E=8.53(10)^{-19} J (4) This is the energy of one 233 nm photon

Substituting (4) in (2):

8.53(10)^{-19} J=6.94(10)^{-19} J+K (5)  

Finding K:

K=1.59(10)^{-19} J (5)  This is the maximum possible kinetic energy of the emitted electrons

<h3>b) Maximum number of electrons that can be freed by a burst of light whose total energy is 2 \mu J=2(10)^{-6} J</h3>

Since one photon of 233 nm is able to free at most one electron from the Titanium metal, we can calculate the following relation:

\frac{E_{burst}}{E}

Where E_{burst}=2(10)^{-6} J is the energy of the burst of light

Hence:

\frac{E_{burst}}{E}=\frac{2(10)^{-6} J}{8.53(10)^{-19} J}=2.34(10)^{12} electrons This is the maximum number of electrons that can be freed by the burst of light.

4 0
3 years ago
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