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soldi70 [24.7K]
3 years ago
7

a 300-gram toy car and a 500-gram toy car are sitting on a shelf that is 2 meters highter than the floor. by what percent is the

PE of the 500-gram car grater than the PE of the 300-gram car?
Physics
2 answers:
andre [41]3 years ago
7 0
We are given:

m1 = 300 grams
m2 = 500 grams
h1 = h2 = 2 meters

We have to determine the potential energy of both toy cars:

PE = mgh
PE1 = m1gh1
PE1 = 300 grams/1000g/kg * 9.81 m/s^2 * 2 meters
PE1 = 5.886 Joules

PE2 = m2gh2
PE2 = 500 grams/1000g/kg * 9.81 m/s^2 * 2 meters
PE2 = 9.81 Joules

PE2 - PE1 / PE2

9.81 - 5.886 Joules / 9.81 joules * 100 = 40.0%

Therefore, the 500-gram car is greater by 40% in terms of potential energy than the 300-gram car. This is because mass is directly proportional to the potential energy of an object. 

White raven [17]3 years ago
4 0

Answer:

66.67% of 500 g Potential energy is greater than that of 300 g of Potential energy.

Explanation:

Height of 300 g mass=h_{1}= 2 m

Height of 500 g mass=h_{2}=2 m

h_{1}=h_{2}

and also gravity remains constant

hence

% of potential energy of 500 g greater than of 300 g=((500-300)/300)*100

% of potential energy greater=(2/3)*100

% of potential energy greater=66.67%  

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<u>Option b. </u>A smaller magnitude of momentum and more kinetic energy.

<h3>What is a momentum?</h3>
  • In Newtonian physics, an object's linear momentum, translational momentum, or simply momentum is defined as the product of its mass and velocity.
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1 year ago
1mm is equal to .1 what
bulgar [2K]

Answer:

When you have to do an English-Metric (SI) length conversion, and you already know the English units of length (miles, yards, feet, inches, etc.), all you need to remember is one simple relationship, and you can readily convert any length in the SI system, to the equivalent length in the other.

1 foot (ft) = 0.3048 meters (m)

BIn this case you need your answer in inches. You (hopefully) know there are 12 inches in a foot, so you just do the following:

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8 0
2 years ago
An electron moving parallel to a uniform electric field increases its speed from 2.0 × 107 m/s to 4.0 × 107 m/s over a distance
jeka94

Answer:

1.8\times 105 N/C

Explanation:

We are given that

u=2\times 10^7 m/s

v=4\times 10^7 m/s

d=1.9 cm=\frac{1.9}{100}=0.019 m

Using 1m=100 cm

We have to find the electric field strength.

v^2-u^2=2as

Using the formula

(4\times 10^7)^2-(2\times 10^7)^2=2a(0.019)

16\times 10^{14}-4\times 10^{14}=0.038a

0.038a=12\times 10^{14}

a=\frac{12}{0.038}\times 10^{14}=3.16\times 10^{16}m/s^2

q=1.6\times 10^{-19} C

Mass of electron,m=9.1\times 10^{-31} kg

E=\frac{ma}{q}

Substitute the values

E=\frac{9.1\times 10^{-31}\times 3.16\times 10^{16}}{1.6\times 10^{-19}}

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7 0
3 years ago
Compare and contrast scientific inquiry "skill and process".
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3 years ago
A 120 kg box is on the verge of slipping down an inclined plane with an angle of inclination of 47º. What is the coefficient of
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Given :

A 120 kg box is on the verge of slipping down an inclined plane with an angle of inclination of 47º.

To Find :

The coefficient of static friction between the box and the plane.

Solution :

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Horizontal component of force(Normal reaction) :

mg\ cos\ \theta =  120\times 10 \times cos\ 47^\circ{}=818.40 \ N

Since, box is on the verge of slipping :

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Therefore, the coefficient of static friction between the box and the plane is 1.07.

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