3 years ago

Which statement explains why weather occurs more quickly in tropical rainforest?

Physics

1 answer:

DENIUS [597]3 years ago

3 0

I think that B is the correct answer to this question.

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The largest salami in the world, made in Norway, was more than 20 m long. If a hungry mouse ran around the salami’s circumferenc

Musya8 [376]

Answer: 0.09 m

Explanation:

Centripetal acceleration in terms of tangential speed is:

$a_c=\frac{v^2_t}{r}$

where r is the radius.

It is given that,

centripetal acceleration of the mouse, $a_c=0.29 m/s^2$

tangential speed , $v_t=0.17m/s$

Radius of salami is:

$r =\frac{(0.17m/s)^2}{0.29 m/s^2}=0.09m$

Thus, the radius of the salami is 0.09 m.

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3 years ago

At its lowest setting a centrifuge rotates with an angular speed of calculate the angular velocity

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No answer is possible until we know the number that belongs after the words "... angular speed of ".

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The equation for density is mass divided by volume. the mass of a substance is changed so that it is made of fewer particles. If

Finger [1]

Density is directly proportional to mass. So if there's less matter inside object, its density will also reduce.

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In gym class you run 22 m horizontally, then climb a rope vertically for 6.2 m. What is the direction angle of your total displa

miskamm [114]

Im 99% sure
tan^-1 (6.2/22)= 15.7º
with 2 significant figures 16º

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The electric field must be zero inside a conductor in electrostatic equilibrium, but not inside an insulator. It turns out that

pav-90 [236]

Answer:

The permittivity of rubber is $\epsilon = 8.703 *10^{-11}$

Explanation:

From the question we are told that

The magnitude of the point charge is $q_1 = 70 \ nC = 70 *10^{-9} \ C$

The diameter of the rubber shell is $d = 32 \ cm = 0.32 \ m$

The Electric field inside the rubber shell is $E = 2500 \ N/ C$

The radius of the rubber is mathematically evaluated as

$r = \frac{d}{2} = \frac{0.32}{2} = 0.16 \ m$

Generally the electric field for a point is in an insulator(rubber) is mathematically represented as

$E = \frac{Q}{ \epsilon } * \frac{1}{4 * \pi r^2}$

Where $\epsilon$ is the permittivity of rubber

=> $E * \epsilon * 4 * \pi * r^2 = Q$

=> $\epsilon = \frac{Q}{E * 4 * \pi * r^2}$

substituting values

$\epsilon = \frac{70 *10^{-9}}{2500 * 4 * 3.142 * (0.16)^2}$

$\epsilon = 8.703 *10^{-11}$

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3 years ago