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Taya2010 [7]
3 years ago
9

Subject: name of 1).6.0.0.), Mu...MC.co.)​

Chemistry
1 answer:
Nata [24]3 years ago
4 0
Dun leo wahei aghdisn apple cat aja Ikooko aq app app ni awọn

















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An evacuated 276 mL glass bulb weighs 129.6375 g. Filled with an unknown gas, the bulb weighs 130.0318 g. Calculate the gas dens
baherus [9]

Answer:

density=1.43 g/L

Explanation:

Since the density formula is density = mass / volume, we need to find out the mass of the gas and the volume is that of the container.

The mass of the gas is  130.0318 g-129.6375 g=0.3943 g

The gas volume is  276mL*(1L/1000mL) 0.276 L

density = mass / volume=0.3943g/0.276L

density =1.43g/L

5 0
3 years ago
Phase changes!a. Write out the Clapeyron equation and explain what it describes.b. Write out the Clausius-Clapeyron equation and
djverab [1.8K]

Answer:

Solutions in the attachment.

Explanation:

4 0
3 years ago
The molecule CCI4 contains one double bond and three single bonds. True or False
kifflom [539]

False

Explanation: Carbon is the central atom which has valency of 4 and can form 4 bonds to complete its octet. Each chlorine has valency of 1 and can form only one bond to complete its octet. Thus carbon can bond with four chlorine atoms through sharing of electrons to form four single bonds. Thus it cannot contain a double bond.

3 0
3 years ago
g For the reaction Ag2S(s)⇌2Ag+(aq)+S2−(aq)Ag2S(s)⇌2Ag+(aq)+S2−(aq), Keq=2.4×10−4Keq=2.4×10−4, and the equilibrium concentration
Roman55 [17]

Answer:

0.32 M

Explanation:

Step 1: Write the balanced reaction at equilibrium

Ag₂S(s) ⇌ 2 Ag⁺(aq) + S²⁻(aq)

Step 2: Calculate the concentration of Ag⁺ at equilibrium

We will use the formula for the concentration equilibrium constant (Keq), which is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. It only includes gases and aqueous species.

Keq = [Ag⁺]² × [S²⁻]

[Ag⁺] = √{Keq / [S²⁻]}

[Ag⁺] = √{2.4 × 10⁻⁴ / 0.0023} = 0.32 M

8 0
3 years ago
How does salt help melt the road?​
QveST [7]

Lower the melting point

Explanation:

Salts helps to melt road by lowering the melting point. It acts as an impurity and generally, impurities low the melting point of substances.

Salts are used as an antifreeze.

  • Water freezes at 0°C and forms ice/snow which can impede human and vehicular movement.
  • When salt is added, it causes the depression of the freezing point by lowering it further.
  • The freezing point is pegged back at -6°C.
  • This way it takes more low temperature to freeze the water.
  • The salt acts as an impurity and causes the depression of melting point and widening of the melting range.

learn more:

Matter brainly.com/question/10972073

#learnwithBrainly

8 0
3 years ago
Read 2 more answers
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