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2 years ago

5

If cars run by lighting gasoline on fire then releasing gas that pushes the wheels to turn, then why can we not run on boiling w

ater since it makes bubbles there for releasing gas just like gasoline?

1 answer:

mezya [45]2 years ago

7 0

Answer:

omg it would burn our insides. we're not made of metal lols

Explanation:

you should mark me as brainliest :)

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Describe the placement of the views in a multi view drawing

Marianna [84]

Answer:

like a mountain place thanks #careonlearning

8 0

2 years ago

Write a simple phonebook program that reads in a series of name-number pairs from the user (that is, name and number on one line

Vlad1618 [11]

Answer:

import java.util.HashMap;

import java.util.Map;

import java.util.Scanner;

public class PhoneBook {

public static void main(String[] args) {

Scanner in = new Scanner(System.in);

Map<String, String> map = new HashMap<>();

String name, number, choice;

do {

System.out.print("Enter name: ");

name = in.next();

System.out.print("Enter number: ");

number = in.next();

map.put(name, number);

System.out.print("Do you want to try again(y or n): ");

choice = in.next();

} while (!choice.equalsIgnoreCase("n"));

System.out.print("Enter name to search for: ");

name = in.next();

if (map.containsKey(name)) {

System.out.println(map.get(name));

} else {

System.out.println(name + " is not in the phone book");

}

}

}

6 0

2 years ago

A liquid phase reaction, A → B, is to be carried out in an isothermal, well mixed batch reactor with a volume of 1L. Initially t

Archy [21]

Answer:

the time, in hours = 4.07hrs

Explanation:

The detailed step by step derivation and appropriate integration is as shown in the attached files.

4 0

2 years ago

A steam turbine in a power plant receives 5 kg/s steam at 3000 kPa, 500°C. Twenty percent of the flow is extracted at 1000 kPa t

MrMuchimi

Answer:

The temperature of the first exit (feed to water heater) is at 330.15ºC. The second exit (exit of the turbine) is at 141ºC. The turbine Power output (if efficiency is %100) is 3165.46 KW

Explanation:

If we are talking of a steam turbine, the work done by the steam is done in an adiabatic process. To determine the temperature of the 2 exits, we have to find at which temperature of the steam with 1000KPa and 200KPa we have the same entropy of the steam entrance.

In this case for steam at 3000 kPa, 500°C, s= 7.2345Kj/kg K. i=3456.18 KJ/Kg

For steam at 1000 kPa and s= 7.2345Kj/kg K → T= 330.15ºC i=3116.48KJ/Kg

For steam at 200 kPa and s= 7.2345Kj/kg K → T= 141ºC i=2749.74KJ/Kg

For the power output, we have to multiply the steam flow with the enthalpic jump.

The addition of the 2 jumps is the total power output.

4 0

3 years ago

A particle moves along a circular path of radius 300 mm. If its angular velocity is θ = (2t) rad/s, where t is in seconds, deter

uysha [10]

Answer:

4.83m/ $s^{2}$

Explanation:

For a particle moving in a circular path the resultant acceleration at any point is the vector sum of radial and the tangential acceleration

Radial acceleration is given by $a_{radial}=w^{2}$ r

Applying values we get $a_{radial}=(2t)^{2}$ X0.3m

Thus $a_{radial}=1.2t^{2}$

At time = 2seconds $a_{radial}= 4.8m/s^{2}$

The tangential acceleration is given by $a_{tangential} =\frac{dV}{dt}=\frac{d(wr)}{dt}$

$a_{tangential}=\frac{d(2tr)}{dt}$

$a_{tangential}= 2r$

$a_{tangential}=0.6m/s^{2}$

Thus the resultant acceleration is given by

$a_{res} =\sqrt{a_{rad}^{2}+a_{tangential}^{2}}$

$a_{res} =\sqrt{4.8^{2}+0.6^{2} } =4.83m/s^{2}$

8 0

3 years ago