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solniwko [45]
3 years ago
9

According to the law of conservation of mass, how would the masses compare?

Physics
1 answer:
Zarrin [17]3 years ago
4 0

Explanation:

According to the law of conservation of mass, the masses at the start and finish of a reaction will stay the same. The law of conservation of mass "mass is always constant in a chemical reaction".

  • The law is the basis for chemical calculations.
  • Masses of reactants and products must be the same to show that mass is always conserved.
  • Disparity in the mass could result from loss of mass to the environment or some side reactions that cannot be easily monitored.

Learn more:

Law of conservation of mass brainly.com/question/5896850

#learnwithBrainly

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What new tool did geologists use to estimate the changing flow rates of lava over the duration of this eruption? Hint: The answe
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Option b, pothographs from drones.

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the USGS (U.S. Geological Survey) decided to make photographic captures from drones to the volcanic surfaces, which allowed through observations to understand things like the characteristics of the lava, the height of the volcanic plumes (among others).

Podemos ver en el siguiente enlace un ejemplo de fotografía tomada desde un dron al Kilauea.

https://www.usgs.gov/media/images/k-lauea-volcano-drone-over-lava-channel

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3 years ago
Jill does twice as much work as Jack does and in half the time. Jill's power output is Group of answer choices one-fourth as muc
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Second Choice.

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Jack's Power = W/t

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2 years ago
A satellite that goes around the earth once every 24 hours (86,400 s) is called a geosynchronous satellite. If a geosynchronous
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The Centripetal force of the satellite is balanced by the universal gravitational force

m\frac{v^2}{r}=\frac{GMm}{r^2}\\\Rightarrow \frac{\left(\frac{2\pi \times r}{24\times 3600}\right)^2}{r}=\frac{6.667\times 10^{-11}\times 5.98\times 10^{24}}{r^2}\\\Rightarrow \left(\frac{2\pi \times r}{24\times 3600}\right)^2=6.667\times 10^{-11}\times 5.98\times 10^{24}\\\Rightarrow r^3=\frac{6.667\times 10^{-11}\times 5.98\times 10^{24}\times (24\times 3600)^2}{(2\pi)^2}\\\Rightarrow r=\left(\frac{6.667\times 10^{-11}\times 5.98\times 10^{24}\times (24\times 3600)^2}{(2\pi)^2}\right)^{\frac{1}{3}}\\\Rightarrow r=42244138.951\ m

The radius as measured from the center of the Earth) of the orbit of a geosynchronous satellite that circles the earth is 42244138.951 m

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