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3 years ago

13

a summer thunderstorm has begun! it’s raining. lighting cracks through air. a few seconds later you hear booms of thunder. why d

o you see the lighting before you hear the thunder?

2 answers:

Afina-wow [57]3 years ago

8 0

Lightning comes before sound, other wise said, light travels faster than sound

Hope this helps.

Illusion [34]3 years ago

4 0

Light travels faster than sound

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One day, Pinki was ironing the clothes in her room. After half an hour of ironing, the light went off and Pinki went outside to

Triss [41]

Answer:

(a) An electric iron works on the heating effect of electric current

(b) The heating effect of an electric current is the tendency for electric current to cause the temperature of the material through which it is flowing to rise due to the resistance of the material

The heating effect, 'E', is given by the formula, E = I²·R·t

Where;

I = The current flowing

R = The resistance of the material

t = The time the material takes to heat up

(c) The values showed by Pinki here is the value of care, concern and prevention, to prevent the harmful effect of the high heat on the skin of her daughter

Explanation:

3 0

3 years ago

A radar station detects an airplane approaching directly from the east. At first observation, the range to the plane is 375.0 m

Gekata [30.6K]

Answer:

819.78 m

Explanation:

<u>Given:</u>

OA = range of initial position of the airplane from the point of observation = 375 m
OB = range of the final position of the airplane from the point of observation = 797 m
$\theta$ = angle of the initial position vector from the observation point = $43^\circ$
$\alpha$ = angle of the final position vector from the observation point = $123^\circ$
$\vec{AB}$ = displacement vector from initial position to the final position

A diagram has been attached with the solution in order to clearly show the position of the plane.

$\vec{OA} = OA\cos \theta \hat{i}+OA \sin \theta \hat{j}\\\Rightarrow \vec{OA} = 375\ m\cos 43^\circ \hat{i}+375\ m\sin 43^\circ \hat{j}\\\Rightarrow \vec{OA} = (274.26\ \hat{i}+255.75\ \hat{j})\ m\\\vec{OB} = OB\cos \alpha \hat{i}+OB \sin \alpha \hat{j}\\\Rightarrow \vec{OB} = 797\ m\cos 123^\circ \hat{i}+797\ m\sin 123^\circ \hat{j}\\\Rightarrow \vec{OB} = (-434.08\ \hat{i}+668.42\ \hat{j})\ m$

Displacement vector of the airplane will be the shortest line joining the initial position of the airplane to the final position of the airplane which is given by:

$\vec{AB}=\vec{OB}-\vec{OA}\\\Rightarrow \vec{AB} = (-434.08\ \hat{i}+668.42\ \hat{j})\ m-(274.26\ \hat{i}+255.75\ \hat{j})\ m\\\Rightarrow \vec{AB} = (-708.34\ \hat{i}+412.67\ \hat{j})\ m$

The magnitude of the displacement vector = $\sqrt{(-708.34)^2+(412.67)^2}\ m = 819.78\ m$

Hence, the magnitude of the displacement of the plane is 819.67 m during the period of observation.

8 0

3 years ago

En una práctica un beisbolista lanza verticalmente la bola con una velocidad de 12m/s en dirección ascendente. ¿Cuál será la alt

fgiga [73]

Answer:

Thus, the maximum height is 7.35 m.

Explanation:

initial velocity, u = 12 m/s

acceleration due to gravity, g = 9.8 m/s^2

Velocity at maximum height, v = 0 m/s

Let the maximum height is h.

Use third equation of motion

$v^{2}=u^{2}-2 g h\\0 = 12\times 12 - 2 \times 9.8\times h\\h =7.35 m$

8 0

3 years ago

A boat moves 60 kilometers east from point A to point B. There, it reverses direction and travels another 45 kilometers toward p

ElenaW [278]

Total distance = 15 kilometers and total displacement = 110 kilometers----- 60 kilometers - 45 kilometers = 15 kilometers 60 + 45 kilometers = 110 kilometers :)))))

3 0

3 years ago

A 500-g lump of clay is dropped onto a 1-kg cart moving at 60 cm/s. The clay is moving downward at 30 cm/s just before l dith t

viktelen [127]

Answer:

The speed of the cart and clay after the collision is 50 cm/s .

Explanation:

Given :

Mass of lump , m = 500 g = 0.5 kg .

Velocity of lump , v = 30 cm/s .

Mass of cart , M = 1 kg .

Velocity of cart , V = 60 cm/s .

We know by conservation of momentum :

$mv+MV=(m+M)v'$

Here , $v'$ is the speed of the cart and clay after the collision .

Putting all value in above equation .

We get :

$0.5\times 30+1\times 60=(0.5+1)\times v'\\\\v'=\dfrac{15+60}{1.5}\\\\v'=50\ cm/s$

Hence , this is the required solution .

3 0

4 years ago