Answer:
The heat capacity for the second process is 15 J/K.
Explanation:
Given that,
Work = 100 J
Change temperature = 5 k
For adiabatic process,
The heat energy always same.


We need to calculate the number of moles and specific heat
Using formula of heat


Put the value into the formula


We need to calculate the heat
Using formula of heat

Put the value into the formula


We need to calculate the heat capacity for the second process
Using formula of heat

Put the value into the formula



Hence, The heat capacity for the second process is 15 J/K.
Answer:
17.5
or
1.1 g/min
I know it's one of these, try getting a second opinion
Answer:
answer is option 4
Explanation:
you have to use option 4 because u need to find out initial velocity (Vi)
The answer is attract. Hope it helps! :)